p=(struct node)malloc(sizeof(struct node));
时间: 2023-09-30 12:03:06 浏览: 62
This line of code is allocating memory dynamically using the malloc() function for a structure called "node". The size of the memory block allocated is determined by the sizeof() function and is the size of the structure "node". The function returns a pointer to the allocated memory block, which is then assigned to the variable "p". This is commonly used in C programming to dynamically allocate memory for data structures at runtime.
相关问题
List p=(List)malloc(sizeof(struct Node))
这行代码是在C语言中动态分配一个结构体类型为Node的内存空间,并将其首地址赋值给指针p。
具体来说,malloc()函数会在内存堆中分配一块大小为sizeof(struct Node)的连续内存空间,并返回这块内存空间的首地址。然后,将这个地址强制转换为List类型的指针,并将其赋值给变量p。
这样做的目的是为了在程序运行时动态地创建一个链表节点,并且可以通过p来访问这个节点的各个成员变量。需要注意的是,这个节点的成员变量的值都是不确定的,需要在程序中进行初始化。同时,使用完这个节点后,还需要使用free()函数释放其内存空间,以避免内存泄漏。
struct Node *newNode = (struct Node*)malloc(sizeof(struct Node))
This line of code allocates memory for a new node in a linked list.
Here's what it does:
- `struct Node*` specifies the data type of the new node, which is a pointer to a struct Node.
- `malloc(sizeof(struct Node))` dynamically allocates memory for the new node with the size of `struct Node`.
- `(struct Node*)` casts the pointer returned by `malloc` to a `struct Node*` data type.
- The resulting pointer is assigned to the pointer variable `newNode`.
Overall, this line of code creates a new node in memory that can be used to store data in a linked list.