Python判断一个人是否色盲
时间: 2023-12-01 11:02:50 浏览: 29
Python可以通过颜色对比度来判断一个人是否色盲。一种简单的方法是使用颜色对比度度量(CCM)算法,该算法使用颜色对比度来计算一个人的色盲程度。下面是一个使用CCM算法的Python代码示例:
```python
def is_color_blind(rgb):
# CCM matrix for protanopia (red deficit) color blindness
ccm_protanopia = [[0.567, 0.433, 0],
[0.558, 0.442, 0],
[0, 0.242, 0.758]]
# CCM matrix for deuteranopia (green deficit) color blindness
ccm_deuteranopia = [[0.625, 0.375, 0],
[0.7, 0.3, 0],
[0, 0.3, 0.7]]
# Convert RGB to LMS color space
lms = [[0.390, 0.768, 0.042],
[0.150, 0.973, 0.876],
[0.060, 0.298, 0.636]]
l, m, s = np.dot(lms, rgb)
# Apply the appropriate CCM matrix based on the type of color blindness
ccm = ccm_protanopia if l > m else ccm_deuteranopia
l_p, m_p, s_p = np.dot(ccm, [l, m, s])
# Convert back to RGB color space
rgb_p = np.dot(np.linalg.inv(lms), [l_p, m_p, s])
# Calculate the color contrast between the original and simulated colors
contrast = color_contrast(rgb, rgb_p)
# A contrast ratio of 4.5 or greater indicates the colors are distinguishable
return contrast >= 4.5
def color_contrast(rgb1, rgb2):
# Convert RGB to grayscale
gray1 = 0.2126 * rgb1[0] + 0.7152 * rgb1[1] + 0.0722 * rgb1[2]
gray2 = 0.2126 * rgb2[0] + 0.7152 * rgb2[1] + 0.0722 * rgb2[2]
# Calculate the color contrast ratio
l1 = (gray1 + 0.05) / (gray2 + 0.05)
l2 = (gray2 + 0.05) / (gray1 + 0.05)
return max(l1, l2)
```
该函数`is_color_blind`接受一个RGB颜色作为参数,并返回一个布尔值来指示该颜色是否在色盲人士中难以区分。如果返回True,则表示该颜色在色盲人士中难以区分;如果返回False,则表示该颜色在色盲人士中易于区分。
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