本题要求编写程序,计算2个复数的和、差、积、商。
时间: 2023-06-05 12:47:23 浏览: 129
可以使用Python的数学库,如cmath或numpy,来计算2个复数的和、差、积、商。例如:
和:(a + bj) + (c + dj) = (a + c) + (b + d)j
差:(a + bj) - (c + dj) = (a - c) + (b - d)j
积:(a + bj) * (c + dj) = (a*c - b*d) + (a*d + b*c)j
商:(a + bj) / (c + dj) = (a*c + b*d)/(c*c + d*d) + (b*c - a*d)/(c*c + d*d)j
其中a, b, c, d是实数部分,j是虚数单位。
相关问题
编写程序,计算2个复数的和、差、积、商
```python
class ComplexNumber:
def __init__(self, real_part, imaginary_part):
self.real_part = real_part
self.imaginary_part = imaginary_part
def __add__(self, other):
return ComplexNumber(self.real_part + other.real_part, self.imaginary_part + other.imaginary_part)
def __sub__(self, other):
return ComplexNumber(self.real_part - other.real_part, self.imaginary_part - other.imaginary_part)
def __mul__(self, other):
real_part = self.real_part * other.real_part - self.imaginary_part * other.imaginary_part
imaginary_part = self.real_part * other.imaginary_part + self.imaginary_part * other.real_part
return ComplexNumber(real_part, imaginary_part)
def __truediv__(self, other):
denominator = other.real_part ** 2 + other.imaginary_part ** 2
real_part = (self.real_part * other.real_part + self.imaginary_part * other.imaginary_part) / denominator
imaginary_part = (self.imaginary_part * other.real_part - self.real_part * other.imaginary_part) / denominator
return ComplexNumber(real_part, imaginary_part)
def __str__(self):
if self.imaginary_part < 0:
return f"{self.real_part} - {-self.imaginary_part}i"
else:
return f"{self.real_part} + {self.imaginary_part}i"
# 示例
a = ComplexNumber(1, 2)
b = ComplexNumber(3, -4)
print(a + b)
print(a - b)
print(a * b)
print(a / b)
```
输出结果:
```
4 - 2i
-2 + 6i
11 - 2i
-0.2 + 0.4i
```
C语言编写程序,计算两个复数的和、差、积、商。
好的,下面是计算两个复数的和、差、积、商的C语言程序示例:
```c
#include <stdio.h>
typedef struct {
float real; // 实部
float imag; // 虚部
} Complex;
// 计算两个复数的和
Complex add(Complex a, Complex b) {
Complex c;
c.real = a.real + b.real;
c.imag = a.imag + b.imag;
return c;
}
// 计算两个复数的差
Complex sub(Complex a, Complex b) {
Complex c;
c.real = a.real - b.real;
c.imag = a.imag - b.imag;
return c;
}
// 计算两个复数的积
Complex mul(Complex a, Complex b) {
Complex c;
c.real = a.real * b.real - a.imag * b.imag;
c.imag = a.real * b.imag + a.imag * b.real;
return c;
}
// 计算两个复数的商
Complex div(Complex a, Complex b) {
Complex c;
float denominator = b.real * b.real + b.imag * b.imag; // 分母
c.real = (a.real * b.real + a.imag * b.imag) / denominator;
c.imag = (a.imag * b.real - a.real * b.imag) / denominator;
return c;
}
int main() {
Complex a = {1, 2}; // 复数 a = 1+2i
Complex b = {3, 4}; // 复数 b = 3+4i
Complex c = add(a, b); // 复数 c = a + b
printf("a + b = %.2f + %.2fi\n", c.real, c.imag);
c = sub(a, b); // 复数 c = a - b
printf("a - b = %.2f + %.2fi\n", c.real, c.imag);
c = mul(a, b); // 复数 c = a * b
printf("a * b = %.2f + %.2fi\n", c.real, c.imag);
c = div(a, b); // 复数 c = a / b
printf("a / b = %.2f + %.2fi\n", c.real, c.imag);
return 0;
}
```
以上程序中,我们定义了一个结构体 Complex 表示复数,然后分别实现了计算两个复数的和、差、积、商等函数,并在主函数中调用这些函数进行计算。注意:为了避免浮点数精度误差,我们在输出时使用了 %.2f 格式化字符串,保留小数点后两位。