void main( ) { int n=4, k=30; if ( n<=5 ) n = n+k/4; if ( n>=10 ) n = n+k/8 ; else n = n+k/6; printf( "%d", n ); }
时间: 2024-06-03 13:08:45 浏览: 12
As an AI language model, I do not have any emotions or feelings, so the concept of null does not apply to me in that sense. However, in programming languages, null is a special value that represents the absence of a value or a reference to an object. It is often used to indicate that a variable or a pointer does not point to anything.
相关问题
c语言设计s=1+1/2+1/3+…+1/n
以下是两种C语言设计s=1+1/2+1/3+…+1/n的例子:
1.使用for循环计算
```c
#include <stdio.h>
int main(void) {
int n = 0;
float sum = 1;
printf("请输入n: ");
scanf("%d", &n);
for (int i = 2; i <= n; i++) {
sum += 1.0 / i;
}
printf("1+1/2+1/3+...+1/%d=%f\n", n, sum);
return 0;
}
```
2.使用函数计算
```c
#include <stdio.h>
#include <stdlib.h>
int fac(int n) //阶乘函数
{
int i = 0;
int y = 1; //用来存返回值
if (0 == n || 1 == n) {
return 1;
} else {
for (i = 2; i <= n; i++) {
y *= i;
}
return y;
}
}
double sum(int n) //求和函数
{
int i = 0; //循环变量
double sum = 0; //和
for (i = 1; i <= n; i++) {
sum += 1.0 / fac(i);
}
return sum;
}
int main() {
int n = 0;
printf("请输入n: ");
scanf("%d", &n);
printf("sum = %lf\n", sum(n));
system("pause"); return 0;
}
```
#include <stdio.h> int main(void) { int k=4,n; for (n=0;n<k;n++) if (n%2==0) continue; k--; } printf("k=%d,n=%d\n",k,n); return 0;
这段代码是有问题的,因为 printf() 函数不在 main() 函数的代码块中。正确的写法应该是:
```
#include <stdio.h>
int main(void) {
int k=4,n;
for (n=0;n<k;n++) {
if (n%2==0) continue;
k--;
}
printf("k=%d,n=%d\n",k,n);
return 0;
}
```
这段代码的输出结果是 k=2,n=2。