TypeError: len() takes exactly one argument (2 given)
时间: 2024-05-15 10:15:27 浏览: 13
This error message is indicating that the `len()` function was given two arguments, but it expected only one.
Here's an example of how this error might occur:
```
my_list = [1, 2, 3]
print(len(my_list, 2))
```
In this code, we're trying to call the `len()` function with two arguments: `my_list` and `2`. However, `len()` expects only one argument (the object whose length we want to find), so it raises a `TypeError`.
To fix this error, we need to pass only one argument to `len()`, like this:
```
my_list = [1, 2, 3]
print(len(my_list))
```
Now, `len()` is receiving only one argument (`my_list`), so it knows what to do and returns the correct length of the list (which is 3, in this case).
相关问题
TypeError: len() takes exactly one argument (2 given)这啥错误
这个错误通常发生在调用 len() 函数时传递了多个参数的情况下。len() 函数只接受一个参数,该参数可以是一个序列、一个映射或一个集合,用于返回该序列、映射或集合中元素的数量。如果传递多个参数,会引发 TypeError 错误。
可能的原因是在调用 len() 函数时,将多个参数传递给它了,例如:
```
len(arg1, arg2)
```
应该将其修改为:
```
len(arg1)
```
或者需要将多个参数合并成一个序列、映射或集合,然后再将其传递给 len() 函数。
TypeError: append() takes exactly one argument (2 given)
这个错误通常是由于在使用append()方法时传递了多个参数导致的。请确保在调用append()方法时只传递了一个参数,例如:
```
my_list = [1, 2, 3]
my_list.append(4)
print(my_list) # 输出 [1, 2, 3, 4]
```
如果您能提供更多的上下文或代码,我可以更具体地帮助您解决问题。