TypeError: set.remove() takes exactly one argument (0 given)
时间: 2024-04-30 09:24:17 浏览: 281
Array.prototype.last:ECMAScript 原生方法的提案
This error occurs when you try to call the `remove()` method on a set without passing any argument. The `remove()` method is used to remove a specific element from a set.
Here's an example of how to use the `remove()` method:
```
my_set = {1, 2, 3, 4}
my_set.remove(3) # removes the element 3 from the set
print(my_set) # prints {1, 2, 4}
```
If the element you're trying to remove is not in the set, you'll get a `KeyError`. To avoid this, you can use the `discard()` method instead, which doesn't raise an error if the element is not in the set:
```
my_set = {1, 2, 3, 4}
my_set.discard(5) # doesn't raise an error, since 5 is not in the set
print(my_set) # prints {1, 2, 3, 4}
```
阅读全文