代码优化 const syncRouter = (table: RouteObjectObj[]): RouteObject[] => { const allRouters: RouteObject[] = [] table.forEach(route => { allRouters.push({ path: route.path, element: route.element ? route.element : route.component && setElement(route.component), children: route.children && syncRouter(route.children) }) }) return allRouters const syncRouter = (table: RouteObjectObj[]): RouteObject[] => { const allRouters: RouteObject[] = [] table.forEach(route => { allRouters.push({ path: route.path, element: route.element ? route.element : route.component && setElement(route.component), children: route.children && syncRouter(route.children) }) }) return allRouters }
时间: 2023-12-15 18:05:07 浏览: 126
const用法详细解释
你提供的代码段有一处问题,即重复了函数定义。需要将其中一段删除。以下是优化后的代码:
```typescript
const syncRouter = (table: RouteObjectObj[]): RouteObject[] => {
const allRouters: RouteObject[] = []
table.forEach(route => {
allRouters.push({
path: route.path,
element: route.element
? route.element
: route.component && setElement(route.component),
children: route.children && syncRouter(route.children)
})
})
return allRouters
}
```
这样,函数定义只出现一次,代码也更加清晰。
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