C++代码编写迷宫问题

以下是C++实现迷宫问题的代码示例：

#include <bits/stdc++.h>
#include <windows.h>
#include <conio.h>
#define ge srand(static_cast<int>(time(NULL)));

using namespace std;

const int MAXN = 1005;
const int MAXM = 1005;

int n, m;
int sx, sy, ex, ey;
int maze[MAXN][MAXM];
int vis[MAXN][MAXM];
int dir[4][2] = {{0, 1}, {0, -1}, {1, 0}, {-1, 0}};

struct node {
    int x, y;
};

stack<node> s;

void gotoxy(int x, int y) {
    COORD pos;
    pos.X = x;
    pos.Y = y;
    SetConsoleCursorPosition(GetStdHandle(STD_OUTPUT_HANDLE), pos);
}

void setColor(int color) {
    SetConsoleTextAttribute(GetStdHandle(STD_OUTPUT_HANDLE), color);
}

void init() {
    memset(maze, 0, sizeof(maze));
    memset(vis, 0, sizeof(vis));
    s = stack<node>();
}

void printMaze() {
    for (int i = 1; i <= n; i++) {
        for (int j = 1; j <= m; j++) {
            if (maze[i][j] == 0) {
                setColor(7);
                cout << "  ";
            } else if (maze[i][j] == 1) {
                setColor(0);
                cout << "■";
            } else if (maze[i][j] == 2) {
                setColor(2);
                cout << "★";
            } else if (maze[i][j] == 3) {
                setColor(4);
                cout << "◆";
            }
        }
        cout << endl;
    }
}

bool dfs(int x, int y) {
    vis[x][y] = 1;
    s.push({x, y});
    if (x == ex && y == ey) {
        while (!s.empty()) {
            node t = s.top();
            s.pop();
            maze[t.x][t.y] = 2;
            printMaze();
            Sleep(100);
        }
        return true;
    }
    for (int i = 0; i < 4; i++) {
        int nx = x + dir[i][0];
        int ny = y + dir[i][1];
        if (nx >= 1 && nx <= n && ny >= 1 && ny <= m && !vis[nx][ny] && maze[nx][ny] == 0) {
            if (dfs(nx, ny)) {
                return true;
            }
        }
    }
    s.pop();
    return false;
}

int main() {
    ge;
    init();
    n = 10, m = 10;
    sx = 1, sy = 1, ex = 10, ey = 10;
    for (int i = 1; i <= n; i++) {
        for (int j = 1; j <= m; j++) {
            if (i == sx && j == sy) {
                maze[i][j] = 0;
            } else if (i == ex && j == ey) {
                maze[i][j] = 0;
            } else {
                maze[i][j] = rand() % 2;
            }
        }
    }
    printMaze();
    dfs(sx, sy);
    setColor(7);
    cout << "Press any key to continue..." << endl;
    _getch();
    return 0;
}