write a C program to swap two number 数据要手动输入

Certainly! Here's a modified version of the program that allows the user to input the two numbers to swap:

#include <stdio.h>

void swap(int *a, int *b);

int main() {
    int num1, num2;

    printf("Enter the first number: ");
    scanf("%d", &num1);

    printf("Enter the second number: ");
    scanf("%d", &num2);

    printf("Before swapping: num1 = %d, num2 = %d\n", num1, num2);

    // call the swap function to swap the values
    swap(&num1, &num2);

    printf("After swapping: num1 = %d, num2 = %d\n", num1, num2);

    return 0;
}

void swap(int *a, int *b) {
    int temp;

    temp = *a;
    *a = *b;
    *b = temp;
}

In this program, we use the `scanf` function to read in two integers from the user, which are stored in the variables `num1` and `num2`. Then, we print out the original values of the variables before swapping them. The `swap` function is the same as in the previous program, which takes in two integer pointers and swaps their values. Finally, we print out the swapped values to confirm that the program works as expected.

I hope that helps! Let me know if you have any further questions.