用python代码做一个贪吃蛇小程序

好的，以下是一个简单的贪吃蛇小程序的 Python 代码：

import pygame
import random

# 初始化 Pygame
pygame.init()

# 设置游戏窗口大小
WINDOW_WIDTH = 800
WINDOW_HEIGHT = 600
WINDOW_SIZE = (WINDOW_WIDTH, WINDOW_HEIGHT)

# 设置游戏窗口标题
pygame.display.set_caption("Snake Game")

# 创建游戏窗口
screen = pygame.display.set_mode(WINDOW_SIZE)

# 设置游戏相关变量
clock = pygame.time.Clock()
snake_block_size = 10
snake_speed = 20

# 定义颜色常量
white = (255, 255, 255)
black = (0, 0, 0)
red = (213, 50, 80)
green = (0, 255, 0)
blue = (50, 153, 213)

# 定义蛇的初始位置和长度
snake_x = WINDOW_WIDTH / 2
snake_y = WINDOW_HEIGHT / 2
snake_length = 1
snake_list = []

# 定义食物的初始位置
food_x = round(random.randrange(0, WINDOW_WIDTH - snake_block_size) / 10.0) * 10.0
food_y = round(random.randrange(0, WINDOW_HEIGHT - snake_block_size) / 10.0) * 10.0

# 定义字体
font_style = pygame.font.SysFont("bahnschrift", 25)

# 定义游戏结束函数
def game_over():
    message = font_style.render("Game Over", True, red)
    screen.blit(message, [WINDOW_WIDTH/3, WINDOW_HEIGHT/3])
    pygame.display.update()
    pygame.time.wait(2000)

# 游戏主循环
game_over_flag = False
while not game_over_flag:

    # 处理游戏事件
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            game_over_flag = True

    # 处理按键事件
    keys = pygame.key.get_pressed()
    if keys[pygame.K_LEFT]:
        snake_x -= snake_block_size
    elif keys[pygame.K_RIGHT]:
        snake_x += snake_block_size
    elif keys[pygame.K_UP]:
        snake_y -= snake_block_size
    elif keys[pygame.K_DOWN]:
        snake_y += snake_block_size

    # 判断蛇是否吃到食物，如果吃到则增加长度并重新生成食物
    if snake_x == food_x and snake_y == food_y:
        food_x = round(random.randrange(0, WINDOW_WIDTH - snake_block_size) / 10.0) * 10.0
        food_y = round(random.randrange(0, WINDOW_HEIGHT - snake_block_size) / 10.0) * 10.0
        snake_length += 1

    # 更新蛇的位置和长度
    snake_head = []
    snake_head.append(snake_x)
    snake_head.append(snake_y)
    snake_list.append(snake_head)
    if len(snake_list) > snake_length:
        del snake_list[0]

    # 判断蛇是否撞墙或撞到自己，如果是则游戏结束
    for block in snake_list[:-1]:
        if block == snake_head:
            game_over_flag = True
    if snake_x < 0 or snake_x >= WINDOW_WIDTH or snake_y < 0 or snake_y >= WINDOW_HEIGHT:
        game_over_flag = True

    # 绘制游戏画面
    screen.fill(black)
    pygame.draw.rect(screen, green, [food_x, food_y, snake_block_size, snake_block_size])
    for block in snake_list:
        pygame.draw.rect(screen, white, [block[0], block[1], snake_block_size, snake_block_size])
    pygame.display.update()

    # 控制游戏帧率
    clock.tick(snake_speed)

# 退出 Pygame
pygame.quit()

运行结果如下所示：