创建一个由6个结点的单向链表，实现结点的增加、删除、查找、移动、遍历显示

好的，我明白了。以下是关于创建一个由6个结点的单向链表的代码实现：

# 定义链表节点类
class ListNode:
    def __init__(self, val):
        self.val = val
        self.next = None

# 定义链表类
class LinkedList:
    def __init__(self):
        self.head = None

    # 实现节点的增加
    def add_node(self, val):
        new_node = ListNode(val)
        if self.head is None:
            self.head = new_node
        else:
            curr = self.head
            while curr.next is not None:
                curr = curr.next
            curr.next = new_node

    # 实现节点的删除
    def delete_node(self, val):
        curr = self.head
        prev = None
        while curr is not None:
            if curr.val == val:
                if prev is None:
                    self.head = curr.next
                else:
                    prev.next = curr.next
                return
            prev = curr
            curr = curr.next

    # 实现节点的查找
    def find_node(self, val):
        curr = self.head
        while curr is not None:
            if curr.val == val:
                return True
            curr = curr.next
        return False

    # 实现节点的移动
    def move_node(self, val, after_val):
        curr = self.head
        while curr is not None:
            if curr.val == val:
                after_node = self.find_node(after_val)
                if after_node is None:
                    return False
                else:
                    curr.next = after_node.next
                    after_node.next = curr
                    return True
            curr = curr.next
        return False

    # 实现链表的遍历显示
    def display_list(self):
        curr = self.head
        while curr is not None:
            print(curr.val)
            curr = curr.next

以上是一个简单的单向链表的实现，其中包括了节点的增加、删除、查找、移动和遍历显示。如果您有任何问题，请随时问我！