python制作五子棋

好的，下面给出一个简单的五子棋游戏实现：

import os

# 初始化棋盘
def init_board():
    board = []
    for i in range(15):
        board.append(['+'] * 15)
    return board

# 打印棋盘
def print_board(board):
    os.system('clear')
    print('   ' + ' '.join([str(i+1) for i in range(15)]))
    for i in range(15):
        print(str(i+1).rjust(2) + ' ' + ' '.join(board[i]))

# 判断胜负
def check_win(board, row, col, ch):
    count = 0
    # 判断横向是否满足胜利条件
    for i in range(15):
        if board[row][i] == ch:
            count += 1
        else:
            count = 0
        if count == 5:
            return True
    # 判断纵向是否满足胜利条件
    count = 0
    for i in range(15):
        if board[i][col] == ch:
            count += 1
        else:
            count = 0
        if count == 5:
            return True
    # 判断左上到右下斜线是否满足胜利条件
    count = 0
    for i in range(-4, 5):
        if row+i < 0 or row+i > 14 or col+i < 0 or col+i > 14:
            continue
        if board[row+i][col+i] == ch:
            count += 1
        else:
            count = 0
        if count == 5:
            return True
    # 判断右上到左下斜线是否满足胜利条件
    count = 0
    for i in range(-4, 5):
        if row+i < 0 or row+i > 14 or col-i < 0 or col-i > 14:
            continue
        if board[row+i][col-i] == ch:
            count += 1
        else:
            count = 0
        if count == 5:
            return True
    return False

# 主程序
def main():
    board = init_board()
    print_board(board)
    player = 'x'
    while True:
        row = int(input('请输入落子的行号（1-15）：')) - 1
        col = int(input('请输入落子的列号（1-15）：')) - 1
        if board[row][col] != '+':
            print('该位置已经有棋子，请重新输入！')
            continue
        board[row][col] = player
        print_board(board)
        if check_win(board, row, col, player):
            print('恭喜玩家%s获胜！' % player)
            break
        if player == 'x':
            player = 'o'
        else:
            player = 'x'

if __name__ == '__main__':
    main()

运行后，将会在终端中显示一个棋盘，玩家可以输入行列坐标来落子，程序会判断胜负并输出结果。