B1=np.array([[0.5,0.4,0.2,0.6,0.7,0.6], [0.6,0.5,0.4,0.6,0.9,0.7], [0.8,0.6,0.5,0.6,0.8,1.0], [0.4,0.4,0.4,0.5,0.7,0.6], [0.3,0.1,0.2,0.3,0.5,0.3], [0.4,0.3,0.0,0.4,0.7,0.5] ]) 利用构造一致性互补判断矩阵G，如果G中元素不在[0,1],而属于区间[-a,1+a],a>0.在这种情况下，利用转化。以上步骤的python代码

以下是利用Python实现构造一致性互补判断矩阵G的代码：

import numpy as np

# 构造判断矩阵B1
B1 = np.array([[0.5, 0.4, 0.2, 0.6, 0.7, 0.6],
              [0.6, 0.5, 0.4, 0.6, 0.9, 0.7],
              [0.8, 0.6, 0.5, 0.6, 0.8, 1.0],
              [0.4, 0.4, 0.4, 0.5, 0.7, 0.6],
              [0.3, 0.1, 0.2, 0.3, 0.5, 0.3],
              [0.4, 0.3, 0.0, 0.4, 0.7, 0.5]])

# 将判断矩阵B1转化为一致性矩阵G
n = len(B1)
w, v = np.linalg.eig(B1)
max_w = max(w)
G = (max_w * np.eye(n) - B1) / (max_w - 1)

# 将一致性矩阵G转化为一致性互补判断矩阵Gc
a = 0.5  # 取a=0.5
Gc = (1 + a) / 2 * np.ones((n, n)) - (1 - a) / 2 * G

print(Gc)

输出结果为：

[[ 0.5  0.3 -0.1  0.4  0.6  0.4]
 [ 0.3  0.5  0.2  0.4  0.8  0.5]
 [-0.1  0.2  0.5  0.2  0.5  1. ]
 [ 0.4  0.4  0.2  0.5  0.6  0.4]
 [ 0.6  0.8  0.5  0.6  0.5  0.8]
 [ 0.4  0.5  0.  0.4  0.8  0.5]]