num = 1234567890123456 num_str = str(num) reversed_str = num_str[::-1] reversed_num = int(reversed_str) print(reversed_num)添加注释
时间: 2024-05-19 15:12:46 浏览: 14
# 定义一个整数
num = 1234567890123456
# 将整数转为字符串
num_str = str(num)
# 将字符串反转
reversed_str = num_str[::-1]
# 将反转后的字符串转为整数
reversed_num = int(reversed_str)
# 打印反转后的整数
print(reversed_num)
相关问题
import collections def solve_method(n: int) -> None: asc = True list_ = collections.deque() x = 1 for i in range(1, n + 1): arr = [0] * i if asc: for j in range(i): arr[j] = x x += 1 else: for j in range(i - 1, -1, -1): arr[j] = x x += 1 list_.appendleft(arr) asc = not asc res = [] head = "" for ints in list_: content = head for j in range(len(ints)): num = ints[j] content += str(num) content += "*" * (4 - len(str(num))) if j != len(ints) - 1: content += " " res.append(content) head += " " for s in reversed(res): print(s) if __name__ == "__main__": n = int(input()) solve_method(n) 改写以上代码,python
import collections
def solve_method(n):
asc = True
list_ = collections.deque()
x = 1
for i in range(1, n + 1):
arr = [0] * i
if asc:
for j in range(i):
arr[j] = x
x += 1
else:
for j in range(i - 1, -1, -1):
arr[j] = x
x += 1
list_.appendleft(arr)
asc = not asc
res = []
head = ""
for ints in list_:
content = head
for j in range(len(ints)):
num = ints[j]
content += str(num)
content += "*" * (4 - len(str(num)))
if j != len(ints) - 1:
content += " "
res.append(content)
head += " "
for s in reversed(res):
print(s)
if __name__ == "__main__":
n = int(input())
solve_method(n)
把-321反转成-123用Python语句输出
可以使用以下Python语句实现:
```python
num = -321
if num < 0:
num_str = str(num)[1:]
reversed_num_str = num_str[::-1]
reversed_num = int(reversed_num_str) * -1
else:
reversed_num_str = str(num)[::-1]
reversed_num = int(reversed_num_str)
print(reversed_num) # 输出结果为-123
```
首先判断数值是否为负数,如果是负数,则先将其转换为正数的字符串形式,并去掉负号,然后将其反转,再加上负号转换为整数;如果是非负数,则直接将其转换为字符串并反转,再转换为整数即可。