for s in "abc": for i in range(3): print(s,end="") if s=="c": break 程序的输出结果和过程及原理
时间: 2024-02-10 07:34:53 浏览: 27
这段程序的输出结果为:abcabcabc。输出过程如下:
- 第一次循环:s = "a",i = 0,输出结果为 "a";
- 第二次循环:s = "a",i = 1,输出结果为 "a";
- 第三次循环:s = "a",i = 2,输出结果为 "a";
- 第四次循环:s = "b",i = 0,输出结果为 "b";
- 第五次循环:s = "b",i = 1,输出结果为 "b";
- 第六次循环:s = "b",i = 2,输出结果为 "b";
- 第七次循环:s = "c",i = 0,输出结果为 "c";
- 第八次循环:s = "c",i = 1,输出结果为 "c";
- 第九次循环:s = "c",i = 2,输出结果为 "c",然后由于满足条件 s=="c",执行 break 语句跳出循环。
该程序的原理是:外层循环遍历字符串 "abc",内层循环遍历数字 0、1、2,然后输出当前字符 s,输出三次后,如果当前字符为 "c",则跳出外层循环。因此最终输出结果为 "abcabcabc"。
相关问题
for s in "abc": for i in range(3): print (s,end="") if s=="c": break
The output of this code would be: "aaabbbccc"
Explanation:
The code consists of a nested loop. The outer loop iterates over each character in the string "abc". The inner loop iterates over the range of values from 0 to 2 (3 times) using the range() function.
During each iteration of the inner loop, the character from the outer loop is printed, using the print() function with the optional argument "end" set to an empty string to suppress the newline character.
When the character "c" is reached during the outer loop, the break statement is executed, which causes the inner loop to terminate immediately. However, the outer loop continues to iterate over the remaining characters in the string "abc", printing each character three times due to the completed inner loop.
下列代码的输出结果是_________。 for s in "abc": for i in range(3): print(s, end = "") if s == "c": break
输出结果是:abcabcabc。在这个嵌套循环中,外部循环遍历字符串 "abc",内部循环遍历 0 到 2 的整数。在每次内部循环中,print(s, end="") 语句输出当前字符串 "abc" 中的字符,因此输出 "abc"。当 s == "c" 时,内部循环被 break 终止,但外部循环仍然继续执行,因此输出结果包含了三个连续的 "abc"。
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