s = "abc123def456"nums = ""for c in s: if c.isdigit(): nums += cresult = int(nums)print(result)用c语言
时间: 2024-05-31 16:08:33 浏览: 12
把Python代码转换为C语言代码如下:
#include <stdio.h>
#include <string.h>
int main() {
char s[] = "abc123def456";
char nums[100] = "";
int result = 0;
int i;
for (i = 0; i < strlen(s); i++) {
if (isdigit(s[i])) {
strncat(nums, &s[i], 1);
}
}
result = atoi(nums);
printf("%d", result);
return 0;
}
相关问题
nums1 = [0, 0, 1] for i in nums1: if i == 0: nums1.remove(i) print(i) 只删除一个零
要只删除一个零,可以使用一个计数器来记录已经删除的零的数量,当删除一个零后,将计数器加1,当计数器等于1时,不再删除零。
下面是修改后的代码:
nums1 = [0, 0, 1]
count = 0
for i in nums1:
if i == 0:
nums1.remove(i)
count += 1
if count == 1:
break
print(nums1) # 输出结果为 [0, 1]
for i in range(n): x=int(input()) if x in nums.keys(): nums[x]+=1 else: nums[x]=1
This code snippet prompts the user to input a number 'n' and then takes 'n' more inputs. It then creates a dictionary 'nums' and checks if the input number already exists as a key in the dictionary. If it does, it sets the value of that key to 1. If it doesn't exist, it adds the number as a new key with a value of 1.
In essence, this code is counting the occurrences of each input number and storing them in a dictionary.
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