int inputValue = System.Int32.Parse(stringValue);解释代码
时间: 2024-03-04 16:53:35 浏览: 85
这行代码的作用是将一个字符串类型的变量 `stringValue` 转换为整数类型的变量 `inputValue`。具体来说,它使用了 `System.Int32` 类的 `Parse` 方法,将字符串类型转换为整数类型。
解释一下代码的执行过程:
1. `stringvalue` 是一个字符串类型的变量,它存储了一个数字的字符串表示,例如 "123"。
2. `System.Int32.Parse` 方法将这个字符串类型的变量作为参数传入,执行字符串到整数的转换。如果字符串无法转换为整数,会抛出异常。
3. 转换后的整数值将赋值给 `inputValue` 变量,可以在后续的代码中使用。
需要注意的是,如果字符串无法转换为整数类型,将会抛出异常。因此,在使用 `Parse` 方法时应该确保字符串的格式是正确的,或者使用 `TryParse` 方法进行安全的转换。
相关问题
Console.WriteLine("Please enter a number:"); int number = int.Parse(Console.ReadLine()); while (number <= 0) { Console.WriteLine("Sorry,please enter a positive value."); number = Int32.Parse(Console.ReadLine()); } Console.WriteLine("Please enter " + number + " words:"); string[] words = new string[number]; for (int n = 0; n < number; n++) { Console.WriteLine($"Please enter word {n + 1}"); string word = Console.ReadLine(); while (word.Length < 1) { Console.WriteLine("Sorry,your word must have at least one character"); word = Console.ReadLine(); } words[n] = word; } Console.WriteLine("You enter these words:"); foreach (string s in words) { Console.WriteLine(s); }; Console.WriteLine("Please enter a character:"); char letter = char.Parse(Console.ReadLine()); if (char.IsLetter(letter)) { string joinedWords = string.Join("", words).ToLower(); int count = 0; for (int i = 0; i < joinedWords.Length; i++) { if (joinedWords[i] == letter) { count++; } } if (count == 0) { Console.WriteLine("The letter you entered does not appear"); } else { double per = Convert.ToDouble(count) / Convert.ToDouble(joinedWords.Length); if (per > 0.25) { Console.WriteLine("The letter " + letter + " appears " + count + " times in the array. This letter makes up more than 25 % of the total number of characters."); } else { Console.WriteLine("The letter " + letter + " appears " + count + " times in the array. This letter makes up less than 25 % of the total number of characters."); } } } else { Console.WriteLine("Incorrect letter format entered,Please enter again:"); letter = char.Parse(Console.ReadLine()); } 改进代码
以下是改进后的代码,主要是加入了异常处理和代码重构:
```csharp
using System;
namespace ConsoleApp
{
class Program
{
static void Main(string[] args)
{
int number = ReadPositiveInt("Please enter a number:");
string[] words = new string[number];
for (int n = 0; n < number; n++)
{
words[n] = ReadNonEmptyString($"Please enter word {n + 1}:");
}
Console.WriteLine("You entered these words:");
foreach (string word in words)
{
Console.WriteLine(word);
}
char letter = ReadLetter("Please enter a character:");
string joinedWords = string.Join("", words).ToLower();
int count = CountLetter(letter, joinedWords);
if (count == 0)
{
Console.WriteLine($"The letter {letter} does not appear");
}
else
{
double per = Convert.ToDouble(count) / Convert.ToDouble(joinedWords.Length);
if (per > 0.25)
{
Console.WriteLine($"The letter {letter} appears {count} times in the array. This letter makes up more than 25% of the total number of characters.");
}
else
{
Console.WriteLine($"The letter {letter} appears {count} times in the array. This letter makes up less than 25% of the total number of characters.");
}
}
}
static int ReadPositiveInt(string message)
{
int number;
while (true)
{
try
{
Console.WriteLine(message);
number = int.Parse(Console.ReadLine());
if (number > 0)
{
return number;
}
else
{
Console.WriteLine("Sorry, please enter a positive value.");
}
}
catch (FormatException)
{
Console.WriteLine("Invalid input format, please enter an integer.");
}
}
}
static string ReadNonEmptyString(string message)
{
string word;
while (true)
{
Console.WriteLine(message);
word = Console.ReadLine();
if (!string.IsNullOrEmpty(word))
{
return word;
}
else
{
Console.WriteLine("Sorry, your word must have at least one character.");
}
}
}
static char ReadLetter(string message)
{
char letter;
while (true)
{
try
{
Console.WriteLine(message);
letter = char.Parse(Console.ReadLine());
if (char.IsLetter(letter))
{
return letter;
}
else
{
Console.WriteLine("Incorrect letter format entered, please enter again:");
}
}
catch (FormatException)
{
Console.WriteLine("Invalid input format, please enter a letter.");
}
}
}
static int CountLetter(char letter, string word)
{
int count = 0;
foreach (char c in word)
{
if (c == letter)
{
count++;
}
}
return count;
}
}
}
```
改进后的代码加入了异常处理,可以更好地处理输入错误的情况。同时,代码也进行了重构,使得逻辑更加清晰,可读性更高。
分析一下此Java代码的parser函数:public boolean parse(String input) { Stack<String> inStack = new Stack<String>(); Stack<String> outStack = new Stack<String>(); outStack.push(startSymbolMap); for (int i = 0; i < input.length(); i++) { inStack.push(String.valueOf(input.charAt(input.length() - 1 - i))); } while (!outStack.isEmpty()) { if (isTerminal(outStack.peek())) { if (outStack.peek().equals(inStack.peek())) { outStack.pop(); inStack.pop(); } else { return false; } } else { Map<String, String> n = parseTable.get(outStack.peek()); String m = n.get(inStack.peek()); if(m!=null){ System.out.println(m); outStack.pop(); for (int k = m.length()-1; k>2; k--) { outStack.push(String.valueOf(m.charAt(k))); } }} } if (outStack.isEmpty() && inStack.isEmpty()) { return true; }else { return false; } }
这是一个简单的自顶向下的语法分析器。该函数接受一个字符串输入,然后按照给定的文法规则进行语法分析。主要分为以下几个步骤:
1. 创建两个栈,一个输入栈 inStack 和一个输出栈 outStack。
2. 将起始符号 startSymbolMap 压入输出栈中。
3. 将输入字符串中的每个字符压入输入栈 inStack 中。
4. 当输出栈不为空时,对栈顶进行判断:
- 如果是终结符号,则与输入栈顶进行比较,如果相等则将两个栈顶元素弹出,否则返回 false。
- 如果是非终结符号,则根据 LL(1) 文法分析表中对应的产生式进行推导,并将产生式右部逆序压入输出栈中。
5. 循环执行步骤 4 直到输出栈为空。
6. 最后判断输入栈和输出栈是否都为空,如果是则返回 true,否则返回 false。
需要注意的是,该函数依赖于一个 LL(1) 文法分析表,该表的结构是一个 Map,其中键为非终结符号,值为一个 Map,其键为终结符号,值为对应的产生式。此外,isTerminal 函数用于判断一个符号是否为终结符号。
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