fun getAddressFromLocation(context: Context,latitude: Double, longitude: Double): String? { val geocoder = Geocoder(context, Locale.getDefault()) val addresses: List<Address>? var addressText = "" try { addresses = geocoder.getFromLocation(latitude, longitude, 1) if (addresses != null && addresses.isNotEmpty()) { val address = addresses[0] val sb = StringBuilder() for (i in 0..address.maxAddressLineIndex) { sb.append(address.getAddressLine(i)).append("\n") } addressText = sb.toString().trim() } } catch (e: IOException) { e.printStackTrace() } return addressText }这个代码如何只获取市

您可以在获取地址的循环中判断地址的类型，如果是市级地址，就只获取对应的部分即可。以下是修改后的代码示例：

fun getCityFromLocation(context: Context, latitude: Double, longitude: Double): String? {
    val geocoder = Geocoder(context, Locale.getDefault())
    val addresses: List<Address>?
    var city = ""

    try {
        addresses = geocoder.getFromLocation(latitude, longitude, 1)
        if (addresses != null && addresses.isNotEmpty()) {
            val address = addresses[0]
            val sb = StringBuilder()

            for (i in 0..address.maxAddressLineIndex) {
                val addressLine = address.getAddressLine(i)
                if (addressLine.contains("市")) {
                    city = addressLine
                    break
                }
            }
        }
    } catch (e: IOException) {
        e.printStackTrace()
    }

    return city
}

在上述代码中，我添加了一个判断，如果地址中包含"市"字，就将该地址赋值给city变量并跳出循环。这样就只获取了市级地址。注意，这里假设返回的地址列表中第一个地址就是最精确的地址，如果需要更多精确度，请根据实际情况进行调整。