c++和汇编语言混合编程程序需要内嵌调用可用DEVC++执行,3个例子
时间: 2024-01-22 11:17:57 浏览: 81
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以下是三个使用C++和汇编语言混合编程的例子,它们可以在Dev-C++中执行。
1. 计算两个整数之和
C++代码:
```cpp
#include <iostream>
using namespace std;
extern "C" int add(int a, int b);
int main() {
int a = 2, b = 3, sum;
sum = add(a, b);
cout << "The sum of " << a << " and " << b << " is " << sum << endl;
return 0;
}
```
汇编代码:
```assembly
.386
.model flat, stdcall
option casemap :none
.code
add PROC
mov eax, DWORD PTR [ebp+8]
add eax, DWORD PTR [ebp+12]
ret
add ENDP
END
```
2. 打印字符串
C++代码:
```cpp
#include <iostream>
using namespace std;
extern "C" void printString(char* str);
int main() {
char* str = "Hello, world!";
printString(str);
return 0;
}
```
汇编代码:
```assembly
.386
.model flat, stdcall
option casemap :none
.code
printString PROC
push ebp
mov ebp, esp
push ebx
mov ebx, DWORD PTR [ebp+8]
mov edx, ebx
mov eax, 4
int 0x80
pop ebx
mov esp, ebp
pop ebp
ret
printString ENDP
END
```
3. 使用汇编实现快速排序
C++代码:
```cpp
#include <iostream>
using namespace std;
extern "C" void quicksort(int* arr, int left, int right);
int main() {
int arr[] = {6, 1, 7, 2, 9, 3, 4, 5, 10, 8};
int len = sizeof(arr) / sizeof(int);
quicksort(arr, 0, len - 1);
for (int i = 0; i < len; i++) {
cout << arr[i] << " ";
}
cout << endl;
return 0;
}
```
汇编代码:
```assembly
.386
.model flat, stdcall
option casemap :none
.code
quicksort PROC
push ebp
mov ebp, esp
push ebx
push esi
push edi
mov esi, DWORD PTR [ebp+8] ; arr
mov ebx, DWORD PTR [ebp+12] ; left
mov edi, DWORD PTR [ebp+16] ; right
cmp ebx, edi
jge QuickSortExit
mov eax, DWORD PTR [esi+ebx*4] ; pivot
mov ecx, ebx
mov edx, edi
jnc QSLoop1
QSLoop2:
dec edx
mov ecx, ebx
jnc QSLoop3
QSLoop1:
inc ecx
cmp ecx, edi
jle QSLoop2
QSLoop3:
cmp ecx, edx
jg QSLoop4
mov eax, DWORD PTR [esi+ecx*4]
mov ebx, DWORD PTR [esi+edx*4]
mov DWORD PTR [esi+ecx*4], ebx
mov DWORD PTR [esi+edx*4], eax
jmp QSLoop2
QSLoop4:
cmp edx, ebx
jg QuickSortRight
mov eax, DWORD PTR [esi+ebx*4]
mov ecx, ebx
dec ecx
QSLoop5:
cmp ecx, -1
jl QSLoop6
cmp DWORD PTR [esi+ecx*4], eax
jg QSLoop7
mov ebx, DWORD PTR [esi+ecx*4]
mov DWORD PTR [esi+(ecx+1)*4], ebx
sub ecx, 1
jmp QSLoop5
QSLoop7:
mov ebx, DWORD PTR [esi+ecx*4]
mov DWORD PTR [esi+(ecx+1)*4], ebx
mov DWORD PTR [esi+ecx*4], eax
QuickSortLeft:
push edi
mov edi, ecx
call quicksort
pop edi
jmp QuickSortRight
QSLoop6:
mov DWORD PTR [esi], eax
QuickSortRight:
inc ebx
cmp ebx, edi
jle QSLoop8
QuickSortExit:
pop edi
pop esi
pop ebx
mov esp, ebp
pop ebp
ret
quicksort ENDP
END
```
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