str = "Hello World" x = len(str) def reversed_str(): reversed_str = "" for i in range(x-1, -1, -1): #从第10个到第0个数 reversed_str = str[i] +reversed_str return reversed_str str = "Hello World" print("The original str is: ") print(str) str2 = reversed_str() print = ("The reversed string is: ") print(str2)
时间: 2023-05-10 10:55:54 浏览: 51
这段代码定义了一个字符串变量 str,其值为 "Hello World"。然后通过 len() 函数获取了 str 的长度,将其赋值给变量 x。接着定义了一个函数 reversed_str(),该函数通过循环将 str 中的字符倒序排列,并将结果保存在变量 reversed_str 中。具体来说,循环从 x-1 开始,每次递减 1,直到循环到第 0 个字符。在循环中,将每个字符依次添加到 reversed_str 的末尾。最后,函数返回变量 reversed_str。
相关问题
num = 1234567890123456 num_str = str(num) reversed_str = num_str[::-1] reversed_num = int(reversed_str) print(reversed_num)添加注释
# 定义一个整数
num = 1234567890123456
# 将整数转为字符串
num_str = str(num)
# 将字符串反转
reversed_str = num_str[::-1]
# 将反转后的字符串转为整数
reversed_num = int(reversed_str)
# 打印反转后的整数
print(reversed_num)
import collections def solve_method(n: int) -> None: asc = True list_ = collections.deque() x = 1 for i in range(1, n + 1): arr = [0] * i if asc: for j in range(i): arr[j] = x x += 1 else: for j in range(i - 1, -1, -1): arr[j] = x x += 1 list_.appendleft(arr) asc = not asc res = [] head = "" for ints in list_: content = head for j in range(len(ints)): num = ints[j] content += str(num) content += "*" * (4 - len(str(num))) if j != len(ints) - 1: content += " " res.append(content) head += " " for s in reversed(res): print(s) if __name__ == "__main__": n = int(input()) solve_method(n) 改写以上代码,python
import collections
def solve_method(n):
asc = True
list_ = collections.deque()
x = 1
for i in range(1, n + 1):
arr = [0] * i
if asc:
for j in range(i):
arr[j] = x
x += 1
else:
for j in range(i - 1, -1, -1):
arr[j] = x
x += 1
list_.appendleft(arr)
asc = not asc
res = []
head = ""
for ints in list_:
content = head
for j in range(len(ints)):
num = ints[j]
content += str(num)
content += "*" * (4 - len(str(num)))
if j != len(ints) - 1:
content += " "
res.append(content)
head += " "
for s in reversed(res):
print(s)
if __name__ == "__main__":
n = int(input())
solve_method(n)