把该学生姓名、选修课程的门数,有哪些选课课程名,实得总学分(某门课及格才能得到学分,否则该课学分为0),输出结果使用一个字符串返回。
时间: 2024-03-11 12:47:37 浏览: 11
好的,我了解了你的问题。对于你的要求,我可以为你提供以下代码:
```python
def get_student_info(name, courses):
credit = 0
course_list = []
for course in courses:
if course["score"] >= 60:
credit += course["credit"]
course_list.append(course["name"])
result = "{}选修了{}门课程,包括{},实得总学分为{}。".format(name, len(courses), "、".join(course_list), credit)
return result
```
其中,`name`表示学生姓名,`courses`是一个列表,每个元素为一个字典,包含了选修课程的名称、学分和成绩,如下所示:
```python
courses = [
{"name": "数学", "credit": 4, "score": 90},
{"name": "英语", "credit": 3, "score": 80},
{"name": "计算机", "credit": 2, "score": 50},
{"name": "物理", "credit": 3, "score": 70}
]
```
你可以调用 `get_student_info` 函数来获取学生的选课信息,例如:
```python
name = "张三"
courses = [
{"name": "数学", "credit": 4, "score": 90},
{"name": "英语", "credit": 3, "score": 80},
{"name": "计算机", "credit": 2, "score": 50},
{"name": "物理", "credit": 3, "score": 70}
]
result = get_student_info(name, courses)
print(result)
```
输出结果为:
```
张三选修了4门课程,包括数学、英语、物理,实得总学分为10。
```
希望这个代码能够帮到你!