function fourthSolve = CreateFourthSolve(number,orderMat,numberMat,distriCenterPosition,customerPosition,N) customerLeave = 1:N; fourthSolve = zeros(1,N); index = 0; for k1 = 1:number disMat = zeros(1,length(customerLeave)); for k2 = 1:length(customerLeave) dis = CalcuDis(distriCenterPosition(orderMat(k1),:),customerPosition(customerLeave(k2),:)); disMat(k2) = dis; end disMat = disMat.^3; disMat = 1./disMat; disMat = disMat/sum(disMat); for k3 = 1:numberMat(k1) index = index+1; number1 = SelectValue(disMat); fourthSolve(index) = customerLeave(number1); customerLeave(number1) = []; disMat(number1) = []; disMat = disMat./sum(disMat); end end显示两侧赋值不统一,是哪出问题了?
时间: 2024-01-28 10:05:55 浏览: 22
这个错误通常是因为 `fourthSolve` 在定义时被初始化为一个长度为 `N` 的全零向量,但在循环过程中,可能没有为 `fourthSolve` 的每一个元素赋值,导致最终向量长度不一致。这可能是因为在循环中,有一些情况下没有执行 `fourthSolve` 的元素赋值操作。
为了解决这个问题,可以在循环结束后再次检查 `fourthSolve` 向量的长度是否与 `N` 相同。可以在循环结束后添加如下代码:
```matlab
if length(fourthSolve) < N
fourthSolve(length(fourthSolve)+1:N) = [];
end
```
这段代码会检查 `fourthSolve` 的长度是否小于 `N` ,如果小于,会将向量的长度扩展至 `N` 并且用零填充剩余的空间。这样可以确保最终的 `fourthSolve` 向量长度为 `N`。
修改后的函数代码如下:
```matlab
function fourthSolve = CreateFourthSolve(number, orderMat, numberMat, distriCenterPosition, customerPosition, N)
customerLeave = 1:N;
fourthSolve = zeros(1, N);
index = 0;
for k1 = 1:number
disMat = zeros(1, length(customerLeave));
for k2 = 1:length(customerLeave)
dis = CalcuDis(distriCenterPosition(orderMat(k1),:), customerPosition(customerLeave(k2),:));
disMat(k2) = dis;
end
disMat = disMat.^3;
disMat = 1./disMat;
disMat = disMat/sum(disMat);
for k3 = 1:numberMat(k1)
index = index+1;
number1 = SelectValue(disMat);
fourthSolve(index) = customerLeave(number1);
customerLeave(number1) = [];
disMat(number1) = [];
disMat = disMat./sum(disMat);
end
end
if length(fourthSolve) < N
fourthSolve(length(fourthSolve)+1:N) = [];
end
```
这样修改后,应该就可以避免这个问题了。