状态空间法野人与修道士Python
时间: 2023-10-14 09:06:04 浏览: 101
好的,您的问题是关于状态空间法和野人与修道士问题的Python实现。那么,我可以给您提供一份基于Python的状态空间法野人与修道士问题的代码示例,供您参考。
代码如下:
```python
# 定义问题状态类
class State:
def __init__(self, left, right, boat):
# 左岸修道士人数
self.left_missionaries = left[0]
# 左岸野人人数
self.left_cannibals = left[1]
# 右岸修道士人数
self.right_missionaries = right[0]
# 右岸野人人数
self.right_cannibals = right[1]
# 船是否在左岸
self.boat_on_left = boat
# 判断当前状态是否合法
def is_valid(self):
if self.left_missionaries < 0 or self.left_cannibals < 0 or self.right_missionaries < 0 or self.right_cannibals < 0:
return False
if self.left_missionaries > 3 or self.left_cannibals > 3 or self.right_missionaries > 3 or self.right_cannibals > 3:
return False
if self.left_cannibals > self.left_missionaries > 0 or self.right_cannibals > self.right_missionaries > 0:
return False
return True
# 判断当前状态是否为目标状态
def is_goal(self):
return self.left_missionaries == 0 and self.left_cannibals == 0
# 判断两个状态是否相等
def __eq__(self, other):
return self.left_missionaries == other.left_missionaries \
and self.left_cannibals == other.left_cannibals \
and self.right_missionaries == other.right_missionaries \
and self.right_cannibals == other.right_cannibals \
and self.boat_on_left == other.boat_on_left
# 获取状态的哈希值
def __hash__(self):
return hash((self.left_missionaries, self.left_cannibals, self.right_missionaries, self.right_cannibals, self.boat_on_left))
# 获取可供选择的下一步状态
def get_next_states(self):
next_states = set()
if self.boat_on_left:
for i in range(3):
for j in range(3):
if i + j > 0 and i + j <= 2:
next_state = State((self.left_missionaries - i, self.left_cannibals - j), (self.right_missionaries + i, self.right_cannibals + j), False)
if next_state.is_valid():
next_states.add(next_state)
else:
for i in range(3):
for j in range(3):
if i + j > 0 and i + j <= 2:
next_state = State((self.left_missionaries + i, self.left_cannibals + j), (self.right_missionaries - i, self.right_cannibals - j), True)
if next_state.is_valid():
next_states.add(next_state)
return next_states
# 定义状态空间搜索类
class StateSpaceSearch:
def __init__(self, init_state, goal_state):
self.init_state = init_state
self.goal_state = goal_state
# 进行状态空间搜索
def search(self):
visited = set()
frontier = [(self.init_state, [])]
while frontier:
state, path = frontier.pop(0)
if state.is_goal():
return path
visited.add(state)
for next_state in state.get_next_states():
if next_state not in visited:
frontier.append((next_state, path + [(state, next_state)]))
return None
# 定义初始状态和目标状态
init_state = State((3, 3), (0, 0), True)
goal_state = State((0, 0), (3, 3), False)
# 进行状态空间搜索
search = StateSpaceSearch(init_state, goal_state)
path = search.search()
# 输出路径
print("The path from the initial state to the goal state is:")
for i, (state, next_state) in enumerate(path):
print("Step", i + 1, ": Take", abs(state.left_missionaries - next_state.left_missionaries), "missionaries and", abs(state.left_cannibals - next_state.left_cannibals), "cannibals from", "left" if state.boat_on_left else "right", "to", "right" if next_state.boat_on_left else "left")
```
以上代码实现了状态空间法野人与修道士问题的Python实现。您可以根据自己的需求进行修改和优化。
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