用java写代码，要求读入4个整数a.b.c.d，根据这4个整数构造两个复数：a+bi和c+di，然后输出它们，并输出它们的和，差，积，商以及上述结果中的最大者(实，虚部运算时均在整数范围内进行运算)

在Java中，你可以按照下面的方式来编写这个程序：

import java.util.Scanner;

class ComplexNumber {
    int real;
    int imaginary;

    // 构造函数
    public ComplexNumber(int a, int b) {
        this.real = a;
        this.imaginary = b;
    }

    // 打印复数
    @Override
    public String toString() {
        return "Complex Number: (" + real + " + " + imaginary + "i)";
    }
}

public class Main {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        
        System.out.println("请输入四个整数:");
        int a = scanner.nextInt();
        int b = scanner.nextInt();
        int c = scanner.nextInt();
        int d = scanner.nextInt();

        // 构造第一个复数
        ComplexNumber num1 = new ComplexNumber(a, b);
        System.out.println("复数1: " + num1);

        // 构造第二个复数
        ComplexNumber num2 = new ComplexNumber(c, d);
        System.out.println("复数2: " + num2);

        // 计算和、差、积、商
        ComplexNumber sum = new ComplexNumber(a+c, b+d);
        System.out.println("和: " + sum);

        ComplexNumber difference = new ComplexNumber(a-c, b-d);
        System.out.println("差: " + difference);

        ComplexNumber product = new ComplexNumber(a*c - b*d, a*d + b*c);
        System.out.println("积: " + product);

        if (b != 0) { // 避免除以零的情况
            ComplexNumber quotient = new ComplexNumber(a*d, b*(c-a));
            System.out.println("商: " + quotient);
        } else {
            System.out.println("商无法计算，除数不能为零");
        }

        // 求最大值（这里假设最大值仅考虑实部）
        int maxReal = Math.max(Math.abs(num1.real), Math.abs(num2.real));
        int maxImaginary = Math.max(Math.abs(num1.imaginary), Math.abs(num2.imaginary));

        System.out.println("实部的最大者: " + (maxReal > 0 ? "+" : "") + maxReal);
        System.out.println("虚部的最大者: " + (maxImaginary > 0 ? "+" : "") + maxImaginary);
    }
}