C++暴力破解NTLM加密算法

暴力破解NTLM加密算法需要对于每个可能的密码进行哈希计算，并将其与目标哈希进行比较。C++可以使用Windows API中的Cryptographic Service Provider (CSP)来实现NTLM哈希计算。以下是一个使用CSP进行NTLM哈希计算的示例代码：

#include <windows.h>
#include <wincrypt.h>
#include <iostream>
#include <string>

bool CrackNTLMHash(const std::string& hash, const std::string& charset, int length, std::string& password)
{
    // Open a handle to the Microsoft Base Cryptographic Provider
    HCRYPTPROV hProv;
    if (!CryptAcquireContext(&hProv, nullptr, MS_DEF_PROV, PROV_RSA_FULL, CRYPT_VERIFYCONTEXT))
    {
        std::cerr << "Failed to acquire cryptographic context\n";
        return false;
    }

    // Convert the hex-encoded hash to binary
    std::string hashBytes;
    for (size_t i = 0; i < hash.length(); i += 2)
    {
        hashBytes += static_cast<char>(std::stoi(hash.substr(i, 2), nullptr, 16));
    }

    // Allocate a buffer for the hash object
    HCRYPTHASH hHash;
    if (!CryptCreateHash(hProv, CALG_MD4, 0, 0, &hHash))
    {
        std::cerr << "Failed to create hash object\n";
        CryptReleaseContext(hProv, 0);
        return false;
    }

    // Iterate over all possible passwords
    std::string passwordHash;
    for (int i = 0; i < length; ++i)
    {
        std::string password(length, charset[0]);
        do
        {
            // Hash the password
            if (!CryptHashData(hHash, reinterpret_cast<const BYTE*>(password.data()), length, 0))
            {
                std::cerr << "Failed to hash data\n";
                CryptDestroyHash(hHash);
                CryptReleaseContext(hProv, 0);
                return false;
            }

            // Get the hash value
            DWORD hashLength = 16;
            BYTE hashValue[16];
            if (!CryptGetHashParam(hHash, HP_HASHVAL, hashValue, &hashLength, 0))
            {
                std::cerr << "Failed to get hash value\n";
                CryptDestroyHash(hHash);
                CryptReleaseContext(hProv, 0);
                return false;
            }

            // Compare the hash value to the target hash
            passwordHash.assign(reinterpret_cast<const char*>(hashValue), hashLength);
            if (passwordHash == hashBytes)
            {
                password = password.substr(0, i) + password[i] + password.substr(i + 1);
                break;
            }

            // Reset the hash object
            if (!CryptDestroyHash(hHash) || !CryptCreateHash(hProv, CALG_MD4, 0, 0, &hHash))
            {
                std::cerr << "Failed to reset hash object\n";
                CryptReleaseContext(hProv, 0);
                return false;
            }
        } while (std::next_permutation(password.begin(), password.end(), [&charset](char a, char b)
        {
            return charset.find(a) < charset.find(b);
        }));
    }

    // Release resources
    CryptDestroyHash(hHash);
    CryptReleaseContext(hProv, 0);

    // Check if the password was found
    if (passwordHash == hashBytes)
    {
        password = password.substr(0, length);
        return true;
    }
    else
    {
        return false;
    }
}

该代码将目标哈希作为十六进制字符串传递，因此您需要将其从NTLM哈希格式转换为十六进制字符串。此外，您需要为字符集和密码长度指定值。代码将在字符集中迭代所有可能的密码，并使用Cryptographic Service Provider计算NTLM哈希。如果找到密码，则将其保存在传递的字符串参数中并返回true，否则返回false。注意，这是一种非常低效的方法，因为它需要尝试所有可能的密码。在现实世界中，密码长度和复杂度通常足以使暴力破解成为不切实际的选择。