color_list = { 0:'None', 1:'red', 2:'green', 3:'blue'}
时间: 2024-01-09 15:03:45 浏览: 23
这是一个Python字典,其中包含四个键值对。键是数字,值是颜色名称。0对应'None',1对应'red',2对应'green',3对应'blue'。可以通过以下代码访问这些值:
```
print(color_list[0]) # 输出 'None'
print(color_list[1]) # 输出 'red'
print(color_list[2]) # 输出 'green'
print(color_list[3]) # 输出 'blue'
```
相关问题
colors=['violet', 'indigo', 'blue','green', 'yellow', 'orange', 'red']
colors=['violet', 'indigo', 'blue','green', 'yellow', 'orange', 'red']是一个将原始列表colors的元素按照逆序列的新列表。将原始列表colors的素从后往前依次赋值给新列表,可以实现逆序排列的效果。这可以通过以下代码实现:new_colors = colors[::-1]。新列表new_colors中的元素顺序为['violet', 'indigo', 'blue','green', 'yellow', 'orange', 'red']。<span class="em">1</span><span class="em">2</span><span class="em">3</span>
#### 引用[.reference_title]
- *1* *2* *3* [【Python入门教程】第32篇 列表切片](https://blog.csdn.net/horses/article/details/122324915)[target="_blank" data-report-click={"spm":"1018.2226.3001.9630","extra":{"utm_source":"vip_chatgpt_common_search_pc_result","utm_medium":"distribute.pc_search_result.none-task-cask-2~all~insert_cask~default-1-null.142^v93^chatsearchT3_2"}}] [.reference_item style="max-width: 100%"]
[ .reference_list ]
python写贪吃蛇1
好的,以下是一个简单的Python贪吃蛇游戏的代码:
```python
import pygame
import time
import random
pygame.init()
white = (255, 255, 255)
black = (0, 0, 0)
red = (213, 50, 80)
green = (0, 255, 0)
blue = (50, 153, 213)
display_width = 600
display_height = 400
display = pygame.display.set_mode((display_width, display_height))
pygame.display.set_caption('Snake Game')
clock = pygame.time.Clock()
snake_block = 10
snake_speed = 15
font_style = pygame.font.SysFont(None, 30)
def message(msg, color):
mesg = font_style.render(msg, True, color)
display.blit(mesg, [display_width / 6, display_height / 3])
def gameLoop():
game_over = False
game_close = False
x1 = display_width / 2
y1 = display_height / 2
x1_change = 0
y1_change = 0
snake_List = []
Length_of_snake = 1
foodx = round(random.randrange(0, display_width - snake_block) / 10.0) * 10.0
foody = round(random.randrange(0, display_height - snake_block) / 10.0) * 10.0
while not game_over:
while game_close == True:
display.fill(black)
message("You Lost! Press Q-Quit or C-Play Again", red)
pygame.display.update()
for event in pygame.event.get():
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_q:
game_over = True
game_close = False
if event.key == pygame.K_c:
gameLoop()
for event in pygame.event.get():
if event.type == pygame.QUIT:
game_over = True
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_LEFT:
x1_change = -snake_block
y1_change = 0
elif event.key == pygame.K_RIGHT:
x1_change = snake_block
y1_change = 0
elif event.key == pygame.K_UP:
y1_change = -snake_block
x1_change = 0
elif event.key == pygame.K_DOWN:
y1_change = snake_block
x1_change = 0
if x1 >= display_width or x1 < 0 or y1 >= display_height or y1 < 0:
game_close = True
x1 += x1_change
y1 += y1_change
display.fill(black)
pygame.draw.rect(display, green, [foodx, foody, snake_block, snake_block])
snake_Head = []
snake_Head.append(x1)
snake_Head.append(y1)
snake_List.append(snake_Head)
if len(snake_List) > Length_of_snake:
del snake_List[0]
for x in snake_List[:-1]:
if x == snake_Head:
game_close = True
for segment in snake_List:
pygame.draw.rect(display, white, [segment[0], segment[1], snake_block, snake_block])
pygame.display.update()
if x1 == foodx and y1 == foody:
foodx = round(random.randrange(0, display_width - snake_block) / 10.0) * 10.0
foody = round(random.randrange(0, display_height - snake_block) / 10.0) * 10.0
Length_of_snake += 1
clock.tick(snake_speed)
pygame.quit()
quit()
gameLoop()
```
这个游戏非常简单,你可以直接复制上面的代码并运行,就可以开始玩游戏了。
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