设计算法，把十进制整数转换为二至九进制之间的任一进制输出。请使用顺序栈和链栈两种数据结构分别设计。(提交伪代码图片)

将十进制整数转换为任意特定进制的过程通常涉及到循环除法和取余操作。以下是使用顺序栈和链栈分别设计的伪代码示例：

**顺序栈实现：**

function decimal_to_arbitrary_stack(decimal, base):
    stack = []
    remainder_stack = Stack()  # 使用顺序栈存储余数
    while decimal > 0:
        remainder = decimal % base
        remainder_stack.push(remainder)
        decimal //= base
    # 将余数从栈顶依次弹出并拼接成字符串
    result = ""
    while not remainder_stack.is_empty():
        result = str(remainder_stack.pop()) + result
    return result

# 示例：
decimal = 123
base = 5
result = decimal_to_arbitrary_stack(decimal, base)

**链栈实现：**

class Node:
    def __init__(self, value=0, next=None):
        self.value = value
        self.next = next

class LinkedListStack:
    def __init__(self):
        self.top = None

    # ... (其他链表栈基本操作)

def decimal_to_linked_list_stack(decimal, base):
    link_stack = LinkedListStack()
    remainder_link_node = Node()
    while decimal > 0:
        remainder = decimal % base
        remainder_link_node.value = remainder
        remainder_link_node.next = link_stack.top
        link_stack.top = remainder_link_node
        decimal //= base
    # 拼接链表结果
    result = ''
    current = link_stack.top
    while current is not None:
        result += str(current.value)
        current = current.next
    return result

# 示例：
decimal = 123
base = 5
result = decimal_to_linked_list_stack(decimal, base)