verilog写可矫正的数字钟代码
时间: 2023-07-29 08:10:23 浏览: 40
以下是一个简单的可矫正的数字钟的Verilog代码示例:
```verilog
module digital_clock(
input clk,
input reset,
output reg [3:0] hour,
output reg [5:0] minute,
output reg [5:0] second
);
reg [27:0] count;
reg [3:0] count_hour;
reg [5:0] count_minute;
reg [5:0] count_second;
reg [3:0] correction_hour;
reg [5:0] correction_minute;
reg [5:0] correction_second;
parameter COUNT_MAX = 100000000; // 最大计数值
parameter SEC_MAX = 60; // 最大秒数
parameter MIN_MAX = 60; // 最大分钟数
parameter HOUR_MAX = 24; // 最大小时数
always @(posedge clk) begin
if (reset) begin
count <= 0;
count_hour <= 0;
count_minute <= 0;
count_second <= 0;
correction_hour <= 0;
correction_minute <= 0;
correction_second <= 0;
hour <= 0;
minute <= 0;
second <= 0;
end else begin
count <= count + 1;
if (count == COUNT_MAX) begin
count <= 0;
count_second <= count_second + 1;
if (count_second == SEC_MAX) begin
count_second <= 0;
count_minute <= count_minute + 1;
if (count_minute == MIN_MAX) begin
count_minute <= 0;
count_hour <= count_hour + 1;
if (count_hour == HOUR_MAX) begin
count_hour <= 0;
end
end
end
end
end
end
always @(posedge clk) begin
if (reset) begin
correction_hour <= 0;
correction_minute <= 0;
correction_second <= 0;
end else begin
if (count == 0) begin
correction_second <= correction_second - 1;
if (correction_second < 0) begin
correction_second <= 59;
correction_minute <= correction_minute - 1;
if (correction_minute < 0) begin
correction_minute <= 59;
correction_hour <= correction_hour - 1;
if (correction_hour < 0) begin
correction_hour <= 23;
end
end
end
end
end
end
always @(posedge clk) begin
if (reset) begin
hour <= 0;
minute <= 0;
second <= 0;
end else begin
hour <= count_hour + correction_hour;
minute <= count_minute + correction_minute;
second <= count_second + correction_second;
end
end
endmodule
```
该代码使用一个内部计数器来跟踪时间,并使用另一个计数器来记录需要进行的矫正值。每当计数器达到最大值时,它将增加下一个单位,并且在必要时进行矫正。