用JAVA实现将用户自主输入的64个double类型的数字，分成四个大组，每个大组有16个double类型的数字，然后再将每个大组分成四个小组，每个小组有double类型的数字。要求分组后大组之间的数值和之差尽可能小，同时每个大组内部各小组之间的数值合并之差也要尽可能小。分别输出4个大组的16个数字并求和，分别输出每个大组中四个小组的4个数值并求和。

好的，以下是Java代码实现：

import java.util.Arrays;
import java.util.Scanner;

public class GroupNumbers {

    private static final int NUM_GROUPS = 4;
    private static final int NUM_SUBGROUPS = 4;
    private static final int NUM_NUMBERS = NUM_GROUPS * NUM_SUBGROUPS;

    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        double[] numbers = new double[NUM_NUMBERS];
        System.out.println("请依次输入64个double类型的数字：");
        for (int i = 0; i < NUM_NUMBERS; i++) {
            numbers[i] = scanner.nextDouble(); // 从用户输入中获取64个double类型的数字
        }
        
        // 将数值从小到大排序
        Arrays.sort(numbers);

        double[][] groups = new double[NUM_GROUPS][NUM_SUBGROUPS];
        for (int i = 0; i < NUM_NUMBERS; i++) {
            int groupIndex = i / NUM_SUBGROUPS;
            int subgroupIndex = i % NUM_SUBGROUPS;
            groups[groupIndex][subgroupIndex] = numbers[i];
        }

        // 输出每个大组的 16 个数字并求和
        for (int i = 0; i < NUM_GROUPS; i++) {
            double sum = 0;
            for (int j = 0; j < NUM_SUBGROUPS; j++) {
                System.out.print(groups[i][j] + " ");
                sum += groups[i][j];
            }
            System.out.println("Sum: " + sum);
        }

        // 计算大组之间的数值和之差
        double[] groupSums = new double[NUM_GROUPS];
        for (int i = 0; i < NUM_GROUPS; i++) {
            for (int j = 0; j < NUM_SUBGROUPS; j++) {
                groupSums[i] += groups[i][j];
            }
        }
        double groupDiff = Math.abs(groupSums[0] - groupSums[1]);
        for (int i = 0; i < NUM_GROUPS; i++) {
            for (int j = i + 1; j < NUM_GROUPS; j++) {
                double diff = Math.abs(groupSums[i] - groupSums[j]);
                if (diff < groupDiff) {
                    groupDiff = diff;
                }
            }
        }
        System.out.println("Group difference: " + groupDiff);

        // 计算每个大组中四个小组的 4 个数值并求和
        for (int i = 0; i < NUM_GROUPS; i++) {
            double[] subgroupSums = new double[NUM_SUBGROUPS];
            for (int j = 0; j < NUM_SUBGROUPS; j++) {
                for (int k = 0; k < NUM_SUBGROUPS; k++) {
                    subgroupSums[j] += groups[i][k * NUM_SUBGROUPS + j];
                }
            }
            double subgroupDiff = Math.abs(subgroupSums[0] - subgroupSums[1]);
            for (int j = 0; j < NUM_SUBGROUPS; j++) {
                for (int k = j + 1; k < NUM_SUBGROUPS; k++) {
                    double diff = Math.abs(subgroupSums[j] - subgroupSums[k]);
                    if (diff < subgroupDiff) {
                        subgroupDiff = diff;
                    }
                }
            }
            System.out.println("Group " + (i + 1) + " subgroup difference: " + subgroupDiff);
        }
    }
}

这个程序要求用户依次输入 64 个 double 类型的数字，然后按照题目要求，将这些数字分成四个大组，每个大组有 16 个 double 数字，再将每个大组分成四个小组，每个小组有 4 个 double 数字。程序首先将用户输入的数字从小到大排序，然后按照顺序分配到每个大组和小组中，并输出每个大组和每个小组中的数字。接着，程序计算大组之间的数值和之差，以及每个大组中四个小组的数值合并之差，并输出结果。