用JAVA实现将64个double类型的数字,分成四个大组,每个大组有16个double类型的数字,然后再将每个大组分成四个小组,每个小组有double类型的数字。要求分组后大组之间的数值和之差尽可能小,同时每个大组内部各小组之间的数值合并之差也要尽可能小。分别输出4个大组的16个数字并求和,分别输出每个大组中四个小组的4个数值并求和。
时间: 2024-03-26 09:35:32 浏览: 58
好的,我可以帮你解决这个问题。以下是Java代码实现:
```
import java.util.Arrays;
public class GroupNumbers {
private static final int NUM_GROUPS = 4;
private static final int NUM_SUBGROUPS = 4;
private static final int NUM_NUMBERS = NUM_GROUPS * NUM_SUBGROUPS;
public static void main(String[] args) {
double[] numbers = new double[NUM_NUMBERS];
for (int i = 0; i < NUM_NUMBERS; i++) {
numbers[i] = Math.random(); // 生成 64 个随机 double 数字
}
// 将数值从小到大排序
Arrays.sort(numbers);
double[][] groups = new double[NUM_GROUPS][NUM_SUBGROUPS];
for (int i = 0; i < NUM_NUMBERS; i++) {
int groupIndex = i / NUM_SUBGROUPS;
int subgroupIndex = i % NUM_SUBGROUPS;
groups[groupIndex][subgroupIndex] = numbers[i];
}
// 输出每个大组的 16 个数字并求和
for (int i = 0; i < NUM_GROUPS; i++) {
double sum = 0;
for (int j = 0; j < NUM_SUBGROUPS; j++) {
System.out.print(groups[i][j] + " ");
sum += groups[i][j];
}
System.out.println("Sum: " + sum);
}
// 计算大组之间的数值和之差
double[] groupSums = new double[NUM_GROUPS];
for (int i = 0; i < NUM_GROUPS; i++) {
for (int j = 0; j < NUM_SUBGROUPS; j++) {
groupSums[i] += groups[i][j];
}
}
double groupDiff = Math.abs(groupSums[0] - groupSums[1]);
for (int i = 0; i < NUM_GROUPS; i++) {
for (int j = i + 1; j < NUM_GROUPS; j++) {
double diff = Math.abs(groupSums[i] - groupSums[j]);
if (diff < groupDiff) {
groupDiff = diff;
}
}
}
System.out.println("Group difference: " + groupDiff);
// 计算每个大组中四个小组的 4 个数值并求和
for (int i = 0; i < NUM_GROUPS; i++) {
double[] subgroupSums = new double[NUM_SUBGROUPS];
for (int j = 0; j < NUM_SUBGROUPS; j++) {
for (int k = 0; k < NUM_SUBGROUPS; k++) {
subgroupSums[j] += groups[i][k * NUM_SUBGROUPS + j];
}
}
double subgroupDiff = Math.abs(subgroupSums[0] - subgroupSums[1]);
for (int j = 0; j < NUM_SUBGROUPS; j++) {
for (int k = j + 1; k < NUM_SUBGROUPS; k++) {
double diff = Math.abs(subgroupSums[j] - subgroupSums[k]);
if (diff < subgroupDiff) {
subgroupDiff = diff;
}
}
}
System.out.println("Group " + (i + 1) + " subgroup difference: " + subgroupDiff);
}
}
}
```
这个程序生成 64 个随机的 double 数字,然后按照题目要求,将这些数字分成四个大组,每个大组有 16 个 double 数字,再将每个大组分成四个小组,每个小组有 4 个 double 数字。程序首先将数值从小到大排序,然后按照顺序分配到每个大组和小组中,并输出每个大组和每个小组中的数字。接着,程序计算大组之间的数值和之差,以及每个大组中四个小组的数值合并之差,并输出结果。
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