二叉树的遍历非递归算法
时间: 2023-11-19 13:51:53 浏览: 87
二叉树的遍历非递归算法可以使用栈来实现。具体来说,对于前序遍历,我们先将根节点入栈,然后每次从栈中取出一个节点,访问它的值,并将其右子节点和左子节点依次入栈;对于中序遍历,我们先将根节点入栈,然后每次从栈中取出一个节点,如果它有左子节点,则将其左子节点入栈,否则访问该节点的值并将其右子节点入栈;对于后序遍历,我们需要记录上一个访问的节点,以便在访问完一个节点的左右子节点后再访问该节点本身。具体实现可以参考下面的代码:
```python
class TreeNode:
def __init__(self, val=0, left=None, right=None):
self.val = val
self.left = left
self.right = right
def preorderTraversal(root: TreeNode) -> List[int]:
if not root:
return []
stack, res = [root], []
while stack:
node = stack.pop()
res.append(node.val)
if node.right:
stack.append(node.right)
if node.left:
stack.append(node.left)
return res
def inorderTraversal(root: TreeNode) -> List[int]:
if not root:
return []
stack, res = [], []
while stack or root:
if root:
stack.append(root)
root = root.left
else:
node = stack.pop()
res.append(node.val)
root = node.right
return res
def postorderTraversal(root: TreeNode) -> List[int]:
if not root:
return []
stack, res, last_visited = [], [], None
while stack or root:
if root:
stack.append(root)
root = root.left
else:
peek = stack[-1]
if peek.right and peek.right != last_visited:
root = peek.right
else:
res.append(peek.val)
last_visited = stack.pop()
return res
```
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