解释代码：const { value } = e.target; const newExpandedKeys = dataList .map((item) => { if (item.title.indexOf(value) > -1) { return getParentKey(item.key, defaultData); } return null; }) .filter((item, i, self) => item && self.indexOf(item) === i); setExpandedKeys(newExpandedKeys as React.Key[]); setSearchValue(value); setAutoExpandParent(true);

这段代码使用了React Hooks中的useState和useEffect钩子函数。它们用于处理React组件的状态和生命周期。

这段代码的作用是根据用户在搜索框中输入的内容，过滤并展开相应的树形菜单节点。

具体的代码逻辑如下：

- const { value } = e.target;：获取用户在搜索框中输入的内容。

- const newExpandedKeys = dataList.map(...)：遍历树形菜单的数据源dataList，根据用户输入的内容过滤出符合条件的节点，并获取它们的父节点的key。

- .filter((item, i, self) => item && self.indexOf(item) === i)：去重过滤，确保只展开每个父节点一次。

- setExpandedKeys(newExpandedKeys as React.Key[])：将符合条件的节点的父节点的key作为新的展开节点设置为组件的状态。

- setSearchValue(value)：将搜索框中的值设置为组件的状态。

- setAutoExpandParent(true)：将自动展开父节点的状态设置为true，确保展开的节点可见。

其中getParentKey函数是一个自定义函数，用于获取节点的父节点的key。

相关问题

优化此代码 const openKeys = ref<string[]>([]) const selectedKeys = ref<string[]>([]) const { currentMenu, currentMenuTree, currentMenuList } = storeToRefs( useLayoutStore(), ) const rootSubmenuKeys = currentMenuList.value.filter((v: any) => { if (v.type === 0) { return v.parentId } }) watch( () => currentMenu, () => { openKeys.value = [currentMenu.value?.parentId] selectedKeys.value = [currentMenu.value?.id] }, { immediate: true }, ) const router = useRouter() /** * 点击事件 * @param e 事件对象 */ const handleClick = (e: any) => { const item = currentMenuList.value.find((_) => _.id === e.key) if (item) { router.push(item.path) } } /** * SubMenu 展开/关闭的回调 * @param e 展开的openKeys */ const onOpenChange = (e: any) => { const latestOpenKey = e.find((key: any) => openKeys.value.indexOf(key) === -1) if (rootSubmenuKeys.indexOf(latestOpenKey) === -1) { openKeys.value = e } else { openKeys.value = latestOpenKey ? [latestOpenKey] : [] } }

There are a few optimizations that could be made to this code:

1. Instead of using `ref` for `openKeys` and `selectedKeys`, you can use `reactive` to make the code more concise:

   const state = reactive({
     openKeys: [],
     selectedKeys: [],
   })

2. Instead of using `storeToRefs` to convert the store state to refs, you can use the `toRefs` function, which is shorter and more concise:

   const { currentMenu, currentMenuTree, currentMenuList } = toRefs(useLayoutStore())

3. Instead of using `watch` to watch the `currentMenu` state changes, you can use a computed property to update the `openKeys` and `selectedKeys` arrays:

   const selectedMenu = computed(() => {
     const item = currentMenuList.value.find((_) => _.id === currentMenu.value?.id)
     return [item?.id] || []
   })

   const parentMenu = computed(() => {
     const item = currentMenuList.value.find((_) => _.id === currentMenu.value?.parentId)
     return [item?.id] || []
   })

   watch([selectedMenu, parentMenu], ([selected, parent]) => {
     state.selectedKeys = selected
     state.openKeys = parent
   })

4. Instead of using `router.push` in the `handleClick` function, you can use the `router.push` method directly in the template:

   <Menu.Item :key="item.id" :to="item.path">{{ item.name }}</Menu.Item>

5. Finally, instead of using `rootSubmenuKeys` to filter the list of menu items, you can use a computed property to filter the list of menu items based on their type:

   const subMenuItems = computed(() => {
     return currentMenuList.value.filter((v: any) => v.type === 0 && v.parentId)
   })

By applying these optimizations, the code can be simplified and made more concise.

const item = medicas.find(item => item.title === title);

这是一个使用 `Array.prototype.find()` 方法在一个数组 `medicas` 中查找一个特定 `title` 属性的值与传入的参数 `title` 相等的对象的代码。如果找到了符合条件的对象，则会将该对象赋值给 `item` 常量，如果没有找到则 `item` 的值为 `undefined`。