Cannot read properties of null (reading 'edgesOut')

根据给出的引用内容，报错"TypeError: Cannot read properties of null (reading 'edgesOut')"是因为在代码中使用了一个为null的对象。可能是由于后端生成的null对象的值导致的。为了解决这个问题，可以进行如下修改：在代码中添加判断条件，如果对象为null，则将对应的属性移除。这样可以避免报错。具体代码修改如下所示：

if (isNull(edgesOut)) {
   curdJsonVm = replace(curdJsonVm, "${edgesOut},", "");
   log.info("model page info:{}", JSONUtil.toJsonPrettyStr(curdJsonVm));
   return curdJsonVm;
}
curdJsonVm = replace(curdJsonVm, "${edgesOut}", JSONObject.toJSONString(edgesOut));

通过这样的修改，就可以避免报错"TypeError: Cannot read properties of null (reading 'edgesOut')"的问题。<span class="em">1</span><span class="em">2</span><span class="em">3</span>
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