北斗广播星历算坐标python

作为AI语言模型，我可以为您提供一些技术指导，但我不能直接为您编写代码。以下是一个基于Python的北斗广播星历算坐标的示例程序：

import math

# 椭球体参数
a = 6378137.0
f = 1.0 / 298.257223563
b = a * (1 - f)
e2 = (a ** 2 - b ** 2) / a ** 2

# 卫星参数
t = 0  # GPS时间
n = 0  # 卫星编号
M0 = 0  # 平近点角
e = 0  # 圆轨道偏心率
a = 0  # 半长轴长度
i0 = 0  # 轨道倾角
omega0 = 0  # 升交点赤经
omega_dot = 0  # 升交点赤经变化率
sqrt_A = 0  # 半长轴的平方根
omega = 0  # 参数
i_dot = 0  # 轨道倾角变化率
IDOT = 0  # 升交点赤纬变化率
Crs = 0  # 半径余弦改正
Crc = 0  # 角度余弦改正
Cus = 0  # 正弦改正
Cuc = 0  # 余弦改正
Cis = 0  # 正弦改正
Cic = 0  # 余弦改正

# 计算卫星的真近点角
n0 = math.sqrt(398600.4418e+12 / a ** 3)
n = n0 + n
M = M0 + n * t
E = M
while True:
    E_old = E
    E = M + e * math.sin(E)
    if abs(E - E_old) < 1e-12:
        break
v = math.atan2(math.sqrt(1 - e ** 2) * math.sin(E), math.cos(E) - e)
phi = v + omega
delta_i = i_dot * t
delta_omega = omega_dot * t - 7.2921151467e-5 * t
delta_u = Cus * math.sin(2 * phi) + Cuc * math.cos(2 * phi)
delta_r = Crs * math.sin(2 * phi) + Crc * math.cos(2 * phi)
delta_i = Cis * math.sin(2 * phi) + Cic * math.cos(2 * phi)
u = phi + delta_u
r = a * (1 - e * math.cos(E)) + delta_r
i = i0 + delta_i

# 计算卫星在地心惯性系下的坐标
x = r * math.cos(u)
y = r * math.sin(u)
z = 0
x1 = x
y1 = y * math.cos(i) - z * math.sin(i)
z1 = y * math.sin(i) + z * math.cos(i)

# 计算卫星在地心地固系下的坐标
W = 7.2921151467e-5 * t
x2 = x1 * math.cos(W) + y1 * math.sin(W)
y2 = -x1 * math.sin(W) + y1 * math.cos(W)
z2 = z1

# 计算卫星在WGS-84坐标系下的经纬度
r2 = math.sqrt(x2 ** 2 + y2 ** 2 + z2 ** 2)
lat = math.asin(z2 / r2)
lon = math.atan2(y2, x2)
h = r2 - a / math.sqrt(1 - e2 * math.sin(lat) ** 2)

# 输出结果
print("卫星编号:", n)
print("经度:", math.degrees(lon))
print("纬度:", math.degrees(lat))
print("高度:", h)