用c++语言在opencv将像素的坐标和梯度信息存入链表
时间: 2023-05-31 20:06:08 浏览: 55
首先,需要定义链表节点的数据结构,包括像素坐标和梯度信息:
```c
typedef struct pixelNode {
int x;
int y;
float dx;
float dy;
struct pixelNode* next;
} PixelNode;
```
然后,可以通过遍历图像的每个像素,获取该像素的坐标和梯度信息,并将其存入链表中:
```c
PixelNode* head = NULL; // 链表头指针
for (int y = 0; y < img.rows; y++) {
for (int x = 0; x < img.cols; x++) {
float dx = 0.0, dy = 0.0;
if (x > 0 && x < img.cols - 1 && y > 0 && y < img.rows - 1) {
dx = img.at<uchar>(y, x + 1) - img.at<uchar>(y, x - 1);
dy = img.at<uchar>(y + 1, x) - img.at<uchar>(y - 1, x);
}
PixelNode* node = (PixelNode*)malloc(sizeof(PixelNode));
node->x = x;
node->y = y;
node->dx = dx;
node->dy = dy;
node->next = head;
head = node;
}
}
```
在此基础上,可以进一步封装成函数,方便调用:
```c
PixelNode* getPixelList(cv::Mat& img) {
PixelNode* head = NULL;
for (int y = 0; y < img.rows; y++) {
for (int x = 0; x < img.cols; x++) {
float dx = 0.0, dy = 0.0;
if (x > 0 && x < img.cols - 1 && y > 0 && y < img.rows - 1) {
dx = img.at<uchar>(y, x + 1) - img.at<uchar>(y, x - 1);
dy = img.at<uchar>(y + 1, x) - img.at<uchar>(y - 1, x);
}
PixelNode* node = (PixelNode*)malloc(sizeof(PixelNode));
node->x = x;
node->y = y;
node->dx = dx;
node->dy = dy;
node->next = head;
head = node;
}
}
return head;
}
```