如何使用python写一个数独游戏
时间: 2024-05-15 17:13:52 浏览: 136
基于Python实现数独游戏【100011897】
实现数独游戏主要分为两个部分:生成数独和交互式游戏界面。下面是一个简单的代码示例,可以实现一个基本的数独游戏。
首先,我们需要导入必要的库:
```python
import random
import copy
import tkinter as tk
```
然后,我们定义一个函数来生成数独:
```python
def generate_sudoku():
base = 3
side = base*base
# pattern for a baseline valid solution
def pattern(r,c): return (base*(r%base)+r//base+c)%side
# randomize rows, columns and numbers (of valid base pattern)
def shuffle(s): return random.sample(s,len(s))
rBase = range(base)
rows = [ g*base + r for g in shuffle(rBase) for r in shuffle(rBase) ]
cols = [ g*base + c for g in shuffle(rBase) for c in shuffle(rBase) ]
nums = shuffle(range(1,base*base+1))
# produce board using randomized baseline pattern
board = [ [nums[pattern(r,c)] for c in cols] for r in rows ]
for i in range(81):
row = i // 9
col = i % 9
if board[row][col] == 0:
for value in range(1, 10):
if value not in board[row]:
if value not in (board[0][col], board[1][col], board[2][col], board[3][col], board[4][col], board[5][col], board[6][col], board[7][col], board[8][col]):
square = []
if row < 3:
if col < 3:
square = [board[i][0:3] for i in range(0, 3)]
elif col < 6:
square = [board[i][3:6] for i in range(0, 3)]
else:
square = [board[i][6:9] for i in range(0, 3)]
elif row < 6:
if col < 3:
square = [board[i][0:3] for i in range(3, 6)]
elif col < 6:
square = [board[i][3:6] for i in range(3, 6)]
else:
square = [board[i][6:9] for i in range(3, 6)]
else:
if col < 3:
square = [board[i][0:3] for i in range(6, 9)]
elif col < 6:
square = [board[i][3:6] for i in range(6, 9)]
else:
square = [board[i][6:9] for i in range(6, 9)]
if value not in (square[0] + square[1] + square[2]):
board[row][col] = value
break
return board
```
该函数会生成一个随机的数独,返回一个 $9\times9$ 的二维数组。
接下来,我们定义一个函数来检查用户输入的答案是否正确:
```python
def check_valid(board, row, col, value):
# check row
if value in board[row]:
return False
# check column
if value in [board[i][col] for i in range(9)]:
return False
# check square
square_row = (row // 3) * 3
square_col = (col // 3) * 3
for i in range(square_row, square_row + 3):
for j in range(square_col, square_col + 3):
if board[i][j] == value:
return False
return True
```
该函数会接受一个数独、用户输入的行、列和值作为参数,并返回一个布尔值,表示该输入是否正确。
最后,我们使用 tkinter 库创建一个交互式游戏界面:
```python
class SudokuGame:
def __init__(self, board):
self.board = board
self.window = tk.Tk()
self.window.geometry('600x600')
self.window.title('数独')
# create cells
self.cells = []
for i in range(9):
row = []
for j in range(9):
cell_value = board[i][j]
if cell_value == 0:
cell = tk.Entry(self.window, width=4, font=('Arial', 20))
cell.bind('<KeyRelease>', lambda event, row=i, col=j: self.check_answer(row, col))
else:
cell = tk.Label(self.window, text=str(cell_value), width=4, font=('Arial', 20))
cell.grid(row=i, column=j)
row.append(cell)
self.cells.append(row)
# create message label
self.message_label = tk.Label(self.window, text='', font=('Arial', 20))
self.message_label.grid(row=9, column=0, columnspan=9)
self.window.mainloop()
def check_answer(self, row, col):
cell_value = self.cells[row][col].get()
if not cell_value.isdigit():
self.cells[row][col].delete(0, tk.END)
return
cell_value = int(cell_value)
if not check_valid(self.board, row, col, cell_value):
self.message_label.config(text='错误')
else:
self.message_label.config(text='')
```
该类会接受一个数独作为参数,创建一个 $9\times9$ 的网格,在网格中使用标签和文本框显示每个单元格的值。当用户输入数字时,会调用 `check_answer` 方法来检查答案是否正确,并在底部的标签中显示错误消息(如果有错误)。
现在,我们可以使用以下代码来生成一个数独游戏:
```python
board = generate_sudoku()
game = SudokuGame(board)
```
运行程序后,就可以在交互式界面中玩数独游戏了。
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