帮我优化下面的代码:qint32 press = channel/2048; QVector<double> temp(channel); if (press == 1){ for (int j = 0;j<16;j++){ for(int i = 0;i<128;i++){ temp<< receiveData[i+j136+2].toInt(nullptr,16); }} }else if (press > 1){ for (int j = 0;j<16;j++){ for(int i = 0;i<128;i++){ for (int k = 0;k<press;k++){ temp<<receiveData[i+j136+2].toInt(nullptr,16); } }} }else if (press < 1){ for (int j = 0;j<16;j++){ for(int i = 0;i<128press;i++){ double s = 0; for (int k = 0;k<int(1/press);k++){ s += receiveData[i+j136+2+k].toInt(nullptr,16); } temp<<s; }} } for (int i = 0 ;i<channel;i++) { scatterEX[i+firstchannel] += temp[i]; }
时间: 2023-06-22 11:41:21 浏览: 95
qint-demo:Qint Quasar应用程序扩展的演示应用程序
可以尝试将三个if语句合并为一个,避免重复的循环。同时,可以使用预处理器指令定义常量,以避免硬编码。最后,可以考虑使用并行化的方法来加速循环计算。优化后的代码如下:
```
#define BLOCK_SIZE 128
#define HEX_BASE 16
qint32 press = channel / 2048;
QVector<double> temp(channel);
#pragma omp parallel for
for (int j = 0; j < 16; j++) {
for (int i = 0; i < BLOCK_SIZE; i++) {
int index = i + j * BLOCK_SIZE + 2;
if (press == 1) {
temp << receiveData[index].toInt(nullptr, HEX_BASE);
} else if (press > 1) {
for (int k = 0; k < press; k++) {
temp << receiveData[index].toInt(nullptr, HEX_BASE);
}
} else if (press < 1) {
double s = 0;
for (int k = 0; k < int(1 / press); k++) {
s += receiveData[index + k].toInt(nullptr, HEX_BASE);
}
temp << s;
}
}
}
#pragma omp parallel for
for (int i = 0; i < channel; i++) {
scatterEX[i + firstchannel] += temp[i];
}
```
注意:如果原代码中的变量 `firstchannel` 是在其他地方定义的,需要在优化后的代码中进行相应的修改。
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