def get_occurrences_of_sequence(original_dataset: [], checked_sequence: ()) -> []:

# I am an AI language model and not sure about the implementation details of your function.
# However, I can provide you with a general outline of how to implement the function.

Here's how you can implement the function:

1. Create an empty list to store the occurrences of the checked sequence
2. Iterate over each element in the original dataset
3. Check if the current element is equal to the first element of the checked sequence
4. If it is, check if the next elements in the original dataset match the remaining elements of the checked sequence
5. If all elements of the checked sequence match, append the index of the occurrence to the list of occurrences
6. Return the list of occurrences

相关问题

def get_cs_with_support_from_occurrences(candidate_set_list: [], number_of_subjects: int) -> []:

frequent_itemsets = []
for candidate_set in candidate_set_list:
support = 0
for subject in range(number_of_subjects):
if all(item in subject for item in candidate_set):
support += 1
if support/number_of_subjects >= 0.5:
frequent_itemsets.append((candidate_set, support/number_of_subjects))
return frequent_itemsets

解释这段代码def get_cs_with_support_from_occurrences(candidate_set_list: [], number_of_subjects: int) -> []:

这段代码定义了一个名为get_cs_with_support_from_occurrences的函数，该函数接受两个参数：一个候选项集列表（candidate_set_list）和一个整数类型的主体数量（number_of_subjects），并返回一个列表。

参数candidate_set_list是一个包含多个候选项集的列表，每个候选项集都是一个由多个项组成的集合。

参数number_of_subjects表示主体数量，即该数据集中的实体数。

函数通过遍历候选项集列表，计算每个候选项集在数据集中出现的次数，并计算其支持度（即出现次数除以主体数量）。最后，将支持度大于0的候选项集及其支持度存储在一个列表中，并返回该列表作为函数的输出。