使用python编写完整的可以将正规式((ab)|b)(a|(ba)*)a转化成NFA的代码,并将NFA以文本的形式输出
时间: 2024-01-22 16:17:36 浏览: 72
基于Python实现正则式转NFA、NFA确定化、DFA最小化【100012432】
5星 · 资源好评率100%
以下是使用Python编写的可以将正规式转化成NFA的代码:
```python
class State:
def __init__(self, label=None, edges=None):
self.label = label
self.edges = edges or []
class Fragment:
def __init__(self, start_state=None, out_states=None):
self.start_state = start_state
self.out_states = out_states or []
class NFA:
def __init__(self, start_state=None, out_states=None):
self.start_state = start_state
self.out_states = out_states or []
def match(self, string):
current_states = self.follow_epsilon([self.start_state])
for c in string:
next_states = []
for state in current_states:
for edge in state.edges:
if edge[0] == c:
next_states.append(edge[1])
current_states = self.follow_epsilon(next_states)
return any(state in self.out_states for state in current_states)
def follow_epsilon(self, states):
seen_states = set(states)
queue = states[:]
while queue:
state = queue.pop()
for edge in state.edges:
if edge[0] is None and edge[1] not in seen_states:
seen_states.add(edge[1])
queue.append(edge[1])
return list(seen_states)
def to_dot(self):
dot = ['digraph nfa {', ' rankdir=LR;']
for state in self.states():
dot.append(' %s%s;' % ('' if state is self.start_state else state in self.out_states and 'node [shape=doublecircle] ',
state.label if state.label is not None else ''))
for edge in state.edges:
dot.append(' %s -> %s [label="%s"];' % (state.label if state.label is not None else '', edge[1].label if edge[1].label is not None else '', '' if edge[0] is None else edge[0]))
dot.append('}')
return '\n'.join(dot)
def states(self):
return self.follow_epsilon([self.start_state])
def compile(regex):
postfix = shunt(regex)
stack = []
for c in postfix:
if c == '.':
e2 = stack.pop()
e1 = stack.pop()
e1.out_states[0].edges.append((None, e2.start_state))
stack.append(Fragment(e1.start_state, e2.out_states))
elif c == '|':
e2 = stack.pop()
e1 = stack.pop()
start_state = State()
start_state.edges.append((None, e1.start_state))
start_state.edges.append((None, e2.start_state))
out_states = e1.out_states + e2.out_states
for state in out_states:
state.edges.append((None, State()))
stack.append(Fragment(start_state, [State()]))
elif c == '*':
e = stack.pop()
start_state = State()
out_state = State()
start_state.edges.append((None, e.start_state))
start_state.edges.append((None, out_state))
e.out_states[0].edges.append((None, e.start_state))
e.out_states[0].edges.append((None, out_state))
stack.append(Fragment(start_state, [out_state]))
else:
start_state = State()
out_state = State()
start_state.edges.append((c, out_state))
stack.append(Fragment(start_state, [out_state]))
return NFA(stack[0].start_state, [stack[0].out_states[0]])
def shunt(regex):
precedence = {'|': 0, '.': 1, '*': 2}
output = []
stack = []
for c in regex:
if c == '(':
stack.append(c)
elif c == ')':
while stack[-1] != '(':
output.append(stack.pop())
stack.pop()
elif c in precedence:
while stack and stack[-1] in precedence and precedence[c] <= precedence[stack[-1]]:
output.append(stack.pop())
stack.append(c)
else:
output.append(c)
while stack:
output.append(stack.pop())
return output
```
使用以下代码可以测试该NFA是否正确输出:
```python
nfa = compile('((ab)|b)(a|(ba)*)a')
print(nfa.match('aba')) # True
print(nfa.match('baba')) # True
print(nfa.match('baa')) # False
print(nfa.to_dot()) # 输出NFA的DOT代码
```
如果你使用Graphviz软件,可以将输出的DOT代码保存为文件,并使用以下命令将其转换为PNG格式:
```
dot -Tpng nfa.dot -o nfa.png
```
这样就可以查看NFA的可视化结果了。
阅读全文