编写一个可以将正规式：((ab)|b)(a|(ba)*)a转化为NFA图的python代码

以下是一个简单的Python代码实现，将给定的正则表达式转换为NFA图：

class State:
    def __init__(self, label=None, edges=None):
        self.label = label
        self.edges = edges or []


class NFA:
    def __init__(self, start=None, end=None):
        self.start = start or State()
        self.end = end or State()
    
    def connect(self, state1, state2):
        state1.edges.append((state2, None))
    
    def match(self, string):
        current_states = self.follow_epsilon([self.start])
        
        for s in string:
            next_states = []
            for state in current_states:
                for edge in state.edges:
                    if edge[1] == s:
                        next_states.append(edge[0])
            current_states = self.follow_epsilon(next_states)
        
        return self.end in current_states
    
    def follow_epsilon(self, states):
        seen = set(states)
        queue = list(states)
        
        while queue:
            state = queue.pop(0)
            for edge in state.edges:
                if edge[1] is None and edge[0] not in seen:
                    seen.add(edge[0])
                    queue.append(edge[0])
        
        return seen


def regex_to_nfa(regex):
    nfa_stack = []
    op_stack = []
    for c in regex:
        if c == '(':
            op_stack.append(c)
        elif c == ')':
            while op_stack and op_stack[-1] != '(':
                op = op_stack.pop()
                if op == '|':
                    nfa2 = nfa_stack.pop()
                    nfa1 = nfa_stack.pop()
                    start = State()
                    end = State()
                    start.edges.append((nfa1.start, None))
                    start.edges.append((nfa2.start, None))
                    nfa1.end.edges.append((end, None))
                    nfa2.end.edges.append((end, None))
                    nfa_stack.append(NFA(start, end))
                elif op == '*':
                    nfa = nfa_stack.pop()
                    start = State()
                    end = State()
                    start.edges.append((nfa.start, None))
                    start.edges.append((end, None))
                    nfa.end.edges.append((nfa.start, None))
                    nfa.end.edges.append((end, None))
                    nfa_stack.append(NFA(start, end))
            op_stack.pop()  # Pop '('
        elif c == '|':
            while op_stack and op_stack[-1] == '*':
                nfa = nfa_stack.pop()
                start = State()
                end = State()
                start.edges.append((nfa.start, None))
                start.edges.append((end, None))
                nfa.end.edges.append((nfa.start, None))
                nfa.end.edges.append((end, None))
                nfa = NFA(start, end)
                nfa_stack.append(nfa)
                op_stack.pop()
            op_stack.append(c)
        elif c == '*':
            nfa = nfa_stack.pop()
            start = State()
            end = State()
            start.edges.append((nfa.start, None))
            start.edges.append((end, None))
            nfa.end.edges.append((nfa.start, None))
            nfa.end.edges.append((end, None))
            nfa = NFA(start, end)
            nfa_stack.append(nfa)
        else:
            start = State()
            end = State()
            start.edges.append((end, c))
            nfa_stack.append(NFA(start, end))
    
    while op_stack:
        op = op_stack.pop()
        if op == '|':
            nfa2 = nfa_stack.pop()
            nfa1 = nfa_stack.pop()
            start = State()
            end = State()
            start.edges.append((nfa1.start, None))
            start.edges.append((nfa2.start, None))
            nfa1.end.edges.append((end, None))
            nfa2.end.edges.append((end, None))
            nfa_stack.append(NFA(start, end))
        elif op == '*':
            nfa = nfa_stack.pop()
            start = State()
            end = State()
            start.edges.append((nfa.start, None))
            start.edges.append((end, None))
            nfa.end.edges.append((nfa.start, None))
            nfa.end.edges.append((end, None))
            nfa = NFA(start, end)
            nfa_stack.append(nfa)
    
    return nfa_stack.pop()


# Test the regex_to_nfa function with the given input regex
regex = '((ab)|b)(a|(ba)*)a'
nfa = regex_to_nfa(regex)

这个代码将给定的正则表达式转换为一个NFA图，并在 `nfa` 变量中返回。你可以根据需要使用它来匹配输入字符串，使用 `nfa.match(input_string)` 方法，该方法将返回一个布尔值，表示输入字符串是否与正则表达式匹配。