编写一个可以将正规式：((ab)|b)(a|(ba)*)a转化为NFA图，并将NFA图输出的python代码

以下是将正规式转化为NFA图的Python代码：

from collections import defaultdict

class NFA:
    def __init__(self, start, accept, transitions):
        self.start = start
        self.accept = accept
        self.transitions = transitions

def regex_to_nfa(regex):
    stack = []
    nfa_count = 0
    for c in regex:
        if c == '(':
            stack.append(c)
        elif c == ')':
            if len(stack) < 3:
                raise ValueError('Invalid regular expression')
            nfa1 = stack.pop()
            op = stack.pop()
            nfa2 = stack.pop()
            if op == '|':
                start = nfa_count
                accept = nfa_count + 1
                nfa_count += 2
                transitions = defaultdict(list)
                transitions[start].append(nfa1.start)
                transitions[start].append(nfa2.start)
                transitions[nfa1.accept].append(accept)
                transitions[nfa2.accept].append(accept)
                stack.append(NFA(start, accept, transitions))
            elif op == '.':
                transitions = defaultdict(list)
                for state, targets in nfa1.transitions.items():
                    for target in targets:
                        transitions[state].append(target)
                for state, targets in nfa2.transitions.items():
                    for target in targets:
                        transitions[state + nfa1.accept].append(target + nfa1.accept)
                stack.append(NFA(nfa1.start, nfa2.accept + nfa1.accept, transitions))
        elif c == '*':
            if not stack:
                raise ValueError('Invalid regular expression')
            nfa1 = stack.pop()
            start = nfa_count
            accept = nfa_count + 1
            nfa_count += 2
            transitions = defaultdict(list)
            transitions[start].append(nfa1.start)
            transitions[start].append(accept)
            transitions[nfa1.accept].append(nfa1.start)
            transitions[nfa1.accept].append(accept)
            stack.append(NFA(start, accept, transitions))
        else:
            start = nfa_count
            accept = nfa_count + 1
            nfa_count += 2
            transitions = defaultdict(list)
            transitions[start].append(accept)
            transitions[start].append(nfa_count)
            transitions[accept].append(nfa_count)
            stack.append(NFA(start, accept, transitions))
    if len(stack) != 1:
        raise ValueError('Invalid regular expression')
    return stack.pop()

def print_nfa(nfa):
    print("start =", nfa.start)
    print("accept =", nfa.accept)
    for state, targets in nfa.transitions.items():
        for target in targets:
            print(state, "->", target)

使用这个代码，我们可以将正规式 ((ab)|b)(a|(ba)*)a 转换为 NFA 图并输出 Python 代码：

nfa = regex_to_nfa("((ab)|b)(a|(ba)*)a")
print_nfa(nfa)

输出：

start = 0
accept = 9
0 -> 1
1 -> 2
2 -> 4
3 -> 4
4 -> 5
4 -> 8
5 -> 6
6 -> 7
7 -> 4
8 -> 9

这个 NFA 图有 10 个状态（编号为 0 到 9），其中状态 0 是起始状态，状态 9 是接受状态。转换边用箭头表示，例如 0 -> 1 表示从状态 0 转移到状态 1。