使用python编写完整的可以将正规式((ab)|b)(a|(ba)*)a转化成NFA的代码，并将NFA以文本的形式输出，并可以使用graphviz进行查看

好的，以下是Python代码实现：

import graphviz

class State:
    def __init__(self, label=None):
        self.transitions = {}
        self.label = label
        self.accepting = False

class NFA:
    def __init__(self, start, end):
        self.start = start
        self.end = end

    def match(self, s):
        current_states = self.get_epsilon_closure([self.start])
        for c in s:
            next_states = []
            for state in current_states:
                if c in state.transitions:
                    next_states += state.transitions[c]
            current_states = self.get_epsilon_closure(next_states)
        return self.end in current_states

    def get_epsilon_closure(self, states):
        closure = set(states)
        stack = list(states)
        while stack:
            state = stack.pop()
            if None in state.transitions:
                for s in state.transitions[None]:
                    if s not in closure:
                        closure.add(s)
                        stack.append(s)
        return closure

def regex_to_nfa(regex):
    stack = []
    start = None
    end = None
    for c in regex:
        if c == '(':
            stack.append((start, end))
            start = None
            end = None
        elif c == ')':
            if not stack:
                raise Exception('Invalid regex')
            prev_start, prev_end = stack.pop()
            if prev_start is not None and prev_end is not None:
                prev_end.transitions[None] = [start]
            if start is not None and end is not None:
                end.transitions[None] = [prev_start]
            start = prev_start
            end = prev_end
        elif c == '|':
            if not stack:
                raise Exception('Invalid regex')
            prev_start, prev_end = stack[-1]
            if prev_start is not None and prev_end is not None:
                prev_end.transitions[None] = [end]
            if start is not None and end is not None:
                end.transitions[None] = [prev_start]
            start = None
            end = None
        elif c == '*':
            if end is None:
                raise Exception('Invalid regex')
            end.transitions[None] = [start]
        else:
            state = State()
            state.transitions[c] = [State()]
            if start is None:
                start = state
            if end is not None:
                end.transitions[None] = [state]
            end = state
    if stack:
        raise Exception('Invalid regex')
    return NFA(start, end)

def nfa_to_dot(nfa):
    dot = graphviz.Digraph()
    dot.node(str(id(nfa.start)), shape='point')
    dot.node(str(id(nfa.end)), shape='doublecircle')
    for state in nfa.get_epsilon_closure([nfa.start]):
        if state is nfa.start:
            continue
        dot.node(str(id(state)), shape='circle', label=state.label)
    for state in nfa.get_epsilon_closure([nfa.start]):
        for c, next_states in state.transitions.items():
            for next_state in next_states:
                dot.edge(str(id(state)), str(id(next_state)), label=c)
    return dot.source

regex = '((ab)|b)(a|(ba)*)a'
nfa = regex_to_nfa(regex)
dot = nfa_to_dot(nfa)
print(dot)

代码实现了将正规式转换为NFA，并将NFA以Graphviz的形式输出。你只需安装Graphviz，然后使用以下命令将输出保存为PNG图像：

dot -Tpng -o nfa.png

其中，`-Tpng`指定输出PNG格式，`-o`指定输出文件名。