python输出贪吃蛇

游戏的代码怎么写？

您好！以下是一个简单的Python代码，可以实现贪吃蛇游戏的输出：

import curses
import time

# 初始化屏幕
screen = curses.initscr()
curses.curs_set(0)
screen_height, screen_width = screen.getmaxyx()

# 初始化蛇的位置和长度
snake = [(screen_height // 2, screen_width // 2)]
snake_length = 1

# 绘制初始蛇和食物
screen.addstr(snake[0][0], snake[0][1], "O")
food = (curses.LINES // 4, curses.COLS // 4)
screen.addstr(food[0], food[1], "@")
screen.refresh()

# 移动蛇
key = curses.KEY_RIGHT
while True:
    new_key = screen.getch()
    key = key if new_key == -1 else new_key
    
    # 计算蛇头的下一个位置
    head = snake[0]
    if key == curses.KEY_DOWN:
        new_head = (head[0] + 1, head[1])
    elif key == curses.KEY_UP:
        new_head = (head[0] - 1, head[1])
    elif key == curses.KEY_LEFT:
        new_head = (head[0], head[1] - 1)
    elif key == curses.KEY_RIGHT:
        new_head = (head[0], head[1] + 1)
    
    # 判断是否撞到墙壁或自身
    if (new_head[0] in [0, screen_height - 1] or
        new_head[1] in [0, screen_width - 1] or
        new_head in snake):
        curses.endwin()
        print("Game over!")
        break
    
    # 移动蛇
    snake.insert(0, new_head)
    screen.addstr(new_head[0], new_head[1], "O")
    
    # 判断是否吃到食物
    if new_head == food:
        food = (curses.LINES // 4, 3 * curses.COLS // 4)
        screen.addstr(food[0], food[1], "@")
        snake_length += 1
    else:
        tail = snake.pop()
        screen.addstr(tail[0], tail[1], " ")
        
    # 更新屏幕
    screen.refresh()
    time.sleep(0.1)

希望能帮到您！