verilog语言实现74160十进制计数器
时间: 2023-08-29 11:05:44 浏览: 157
verilog实现计数器设计
Verilog代码如下:
```
module counter (
input clk,
input rst,
output reg [3:0] count_out
);
always @(posedge clk or posedge rst) begin
if (rst) begin
count_out <= 0;
end else begin
case (count_out)
4'b0000: count_out <= 4'b0001;
4'b0001: count_out <= 4'b0010;
4'b0010: count_out <= 4'b0011;
4'b0011: count_out <= 4'b0100;
4'b0100: count_out <= 4'b0101;
4'b0101: count_out <= 4'b0110;
4'b0110: count_out <= 4'b0111;
4'b0111: count_out <= 4'b1000;
4'b1000: count_out <= 4'b1001;
4'b1001: count_out <= 4'b0000;
endcase
end
end
endmodule
```
这个模块实现了一个4位十进制计数器,当clk为正极沿触发时,计数器会递增一位,当rst为正极沿触发时,计数器会被清零。计数器的最大值为9,所以当计数器的值达到9时,下一个值会再次从0开始计数。
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