Verilog慢速十进制计数器
时间: 2023-08-20 22:06:55 浏览: 54
使用Verilog实现一个慢速的十进制计数器的代码如下:
```
module slow_decimal_counter(clk, reset, out);
input clk, reset;
output reg [3:0 out;
reg [3:0 count;
always @(posedge clk or posedge reset) begin
if(reset)
count <= 0;
else if(count == 9)
count <= 0;
else
count <= count + 1;
end
always @(posedge clk) begin
if(reset)
out <= 0;
else
out <= count;
end
endmodule
```
这个慢速的十进制计数器使用一个4位的寄存器(count)来存储当前的计数值,每当时钟上升沿到来时,计数器会增加1。当计数器达到9时,会被重置为0。输出(out)会根据计数器的值进行更新。
请注意,这只是一个简单的慢速十进制计数器的实现,并不考虑实际的硬件约束和优化。实际的设计中可能需要添加其他逻辑来实现更复杂的功能。<span class="em">1</span><span class="em">2</span><span class="em">3</span>
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