TreeSet对象排序：创建学生类 属性包括姓名，年龄，Java成绩，英语成绩。 创建5个学生对象，存入TreeSet集合中，排序规则是： 按总分从高到低； 如果总分一样，按Java成绩排序； 如果Java成绩一样，按年龄排序； 如果年龄一样，按姓名的字母顺序排序。 如果都一样，认为是同一个学生，不存。

好的，这个问题比较简单，我可以回答。请先看一下我给出的代码实现：

import java.util.*;

class Student implements Comparable<Student>{
    String name;
    int age;
    int javaScore;
    int englishScore;
 
    public Student(String name, int age, int javaScore, int englishScore) {
        this.name = name;
        this.age = age;
        this.javaScore = javaScore;
        this.englishScore = englishScore;
    }
 
    public int compareTo(Student other) {
        int totalScore = this.javaScore + this.englishScore;
        int otherTotalScore = other.javaScore + other.englishScore;
        if(totalScore != otherTotalScore) {
            return otherTotalScore - totalScore;
        } else if(this.javaScore != other.javaScore) {
            return other.javaScore - this.javaScore;
        } else if(this.age != other.age) {
            return this.age - other.age;
        } else {
            return this.name.compareTo(other.name);
        }
    }
 
    public boolean equals(Object obj){
        if(obj instanceof Student){
            Student other=(Student)obj;
            return this.name.equals(other.name) && this.age == other.age && this.javaScore == other.javaScore && this.englishScore == other.englishScore;
        }
        return super.equals(obj);
    }
 
    public int hashCode(){
        return Objects.hash(name, age, javaScore, englishScore);
    }
}
 
public class Main {
    public static void main(String[] args) {
        Student s1 = new Student("张三", 18, 90, 80);
        Student s2 = new Student("李四", 17, 80, 90);
        Student s3 = new Student("王五", 18, 90, 70);
        Student s4 = new Student("赵六", 18, 90, 80);
        Student s5 = new Student("陈七", 19, 80, 90);
 
        TreeSet<Student> set = new TreeSet<>();
        set.add(s1);
        set.add(s2);
        set.add(s3);
        set.add(s4);
        set.add(s5);
 
        for(Student s : set) {
            System.out.println(s.name + " " + s.age + " " + s.javaScore + " " + s.englishScore);
        }
    }
}

我重写了Student类的compareTo方法，以便排序。我们需要先将学生对象存入TreeSet集合中，然后输出集合中的元素即可。按照规则，输出结果应该是这样的：

张三 18 90 80
赵六 18 90 80
陈七 19 80 90
王五 18 90 70
李四 17 80 90

如果你有任何问题，可以继续问我。