C++ user-defined literal operator not found
时间: 2023-10-02 17:08:48 浏览: 118
This error message typically occurs when you try to use a user-defined literal in your code, but the corresponding user-defined literal operator is not defined or not visible to the compiler.
To fix this error, you need to define the user-defined literal operator in your code. Here is an example:
```cpp
#include <iostream>
// Define a user-defined literal operator for meters
constexpr long double operator"" _m(long double meters) {
return meters;
}
int main() {
// Use the user-defined literal operator to create a length measurement in meters
long double length = 2.5_m;
std::cout << "Length: " << length << " meters" << std::endl;
return 0;
}
```
In this example, we define a user-defined literal operator for meters, which takes a long double argument representing the length in meters. We use the operator"" _m syntax to define the operator, where _m is the suffix we use to indicate meters. We then use the operator to create a length measurement in meters, which we output to the console.
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