SELECT COUNT(DISTINCT another_field), SUM(CASE WHEN your_field = your_condition_1 THEN 1 ELSE 0 END) AS count_1, SUM(CASE WHEN your_field = your_condition_2 THEN 1 ELSE 0 END) AS count_2, SUM(CASE WHEN your_field = your_condition_3 THEN 1 ELSE 0 END) AS count_3FROM your_table;这条语句里怎么让your_field 不加group by根据another_field去重

时间: 2024-03-12 22:45:32 浏览: 15
在 Oracle 中,如果您不想使用 `GROUP BY` 子句,可以使用子查询来实现按 `another_field` 字段去重的效果: ``` SELECT COUNT(DISTINCT another_field), SUM(CASE WHEN your_field = your_condition_1 THEN 1 ELSE 0 END) AS count_1, SUM(CASE WHEN your_field = your_condition_2 THEN 1 ELSE 0 END) AS count_2, SUM(CASE WHEN your_field = your_condition_3 THEN 1 ELSE 0 END) AS count_3 FROM ( SELECT DISTINCT another_field, your_field FROM your_table ) subquery; ``` 这条 SQL 语句将会先对 `your_table` 表进行去重,使用 `DISTINCT` 关键字按 `another_field` 和 `your_field` 字段分别去重,然后再在子查询的结果上进行统计操作。这样,查询结果将会根据 `another_field` 字段去重,并对每个不同的 `another_field` 值分别统计 `your_field` 字段的数量。
相关问题

SELECT COUNT(DISTINCT another_field), SUM(CASE WHEN your_field = your_condition_1 THEN 1 ELSE 0 END) AS count_1, SUM(CASE WHEN your_field = your_condition_2 THEN 1 ELSE 0 END) AS count_2, SUM(CASE WHEN your_field = your_condition_3 THEN 1 ELSE 0 END) AS count_3FROM your_table;这条语句里怎么让your_field根据another_field去重

如果您需要让 `your_field` 字段根据 `another_field` 字段去重,可以在 `COUNT` 函数和 `GROUP BY` 子句中分别使用 `DISTINCT another_field`: ``` SELECT COUNT(DISTINCT another_field), SUM(CASE WHEN your_field = your_condition_1 THEN 1 ELSE 0 END) AS count_1, SUM(CASE WHEN your_field = your_condition_2 THEN 1 ELSE 0 END) AS count_2, SUM(CASE WHEN your_field = your_condition_3 THEN 1 ELSE 0 END) AS count_3 FROM your_table GROUP BY DISTINCT another_field; ``` 这样,查询结果将会根据 `another_field` 字段去重,并对每个不同的 `another_field` 值分别统计 `your_field` 字段的数量。

select case when count(*) =0 then '0' else distinct a end as result from abc

在你的查询中,你可以使用以下语法来处理值为空时返回 '0',不为空时返回去重后的结果: ```sql SELECT CASE WHEN COUNT(*) = 0 THEN '0' ELSE (SELECT DISTINCT a FROM abc) END AS result FROM abc; ``` 在这个示例中,我们首先使用 COUNT(*) 函数来计算行数,以判断是否所有值为空。如果行数为 0,则返回 '0';否则,使用子查询 `(SELECT DISTINCT a FROM abc)` 来获取去重后的结果,并将结果赋值给别名 `result`。 请注意,这个示例假设子查询 `(SELECT DISTINCT a FROM abc)` 返回的结果只有一列,如果有多列,则需要相应地调整查询逻辑。 根据你的具体需求和数据结构,你可以进行适当的调整。

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优化代码,并提供新脚本SELECT SUM(CASE WHEN order_date BETWEEN '2022-10-31' AND '2022-11-11' AND is_new_customer = 1 THEN 1 ELSE 0 END) AS new_customer_count, SUM(CASE WHEN order_date BETWEEN '2022-10-31' AND '2022-11-11' AND is_new_customer = 0 THEN 1 ELSE 0 END) AS old_customer_count, SUM(CASE WHEN order_date BETWEEN '2022-10-31' AND '2022-11-11' AND is_new_customer = 1 THEN payment_amount ELSE 0 END) AS new_customer_payment_amount, SUM(CASE WHEN order_date BETWEEN '2022-10-31' AND '2022-11-11' AND is_new_customer = 0 THEN payment_amount ELSE 0 END) AS old_customer_payment_amount, SUM(CASE WHEN order_date BETWEEN '2022-10-31' AND '2022-11-11' THEN CASE WHEN category = 'A' THEN 1 ELSE 0 END ELSE 0 END) AS category_A_customer_count, SUM(CASE WHEN order_date BETWEEN '2022-10-31' AND '2022-11-11' THEN CASE WHEN category = 'A' THEN payment_amount ELSE 0 END ELSE 0 END) AS category_A_payment_amount, SUM(CASE WHEN order_date BETWEEN '2022-10-31' AND '2022-11-11' THEN CASE WHEN category = 'B' THEN 1 ELSE 0 END ELSE 0 END) AS category_B_customer_count, SUM(CASE WHEN order_date BETWEEN '2022-10-31' AND '2022-11-11' THEN CASE WHEN category = 'B' THEN payment_amount ELSE 0 END ELSE 0 END) AS category_B_payment_amount, SUM(CASE WHEN order_date BETWEEN '2022-10-31' AND '2022-11-11' THEN CASE WHEN product_id = 'P1' THEN 1 ELSE 0 END ELSE 0 END) AS product_P1_customer_count, SUM(CASE WHEN order_date BETWEEN '2022-10-31' AND '2022-11-11' THEN CASE WHEN product_id = 'P1' THEN payment_amount ELSE 0 END ELSE 0 END) AS product_P1_payment_amount FROM orders WHERE (order_date BETWEEN '2022-10-31' AND '2022-11-11') OR (order_date BETWEEN '2021-10-31' AND '2022-10-30' AND order_date NOT IN (SELECT order_date FROM orders WHERE order_date BETWEEN '2022-10-31' AND '2022-11-11')) OR (order_date BETWEEN '2021-11-12' AND '2022-10-30' AND order_date IN (SELECT order_date FROM orders WHERE order_date BETWEEN '2022-10-31' AND '2022-11-11'))

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