for a in range (1,10): for b in range (1,10): for c in range (1,10): s1=a*100+b*10+c s2=a**3+b**3+c**3 if s1==s2: print (s1)
时间: 2023-05-24 11:05:32 浏览: 80
This code is written in Python and it prints out all the Armstrong numbers between 100 and 999.
An Armstrong number is a number that is equal to the sum of its own digits raised to the power of the number of digits in the number.
For example, 153 is an Armstrong number because:
1^3 + 5^3 + 3^3 = 1 + 125 + 27 = 153
The code uses three nested loops to generate all three-digit numbers from 100 to 999. For each number, it calculates the sum of its digits raised to the third power and compares it to the original number. If they are equal, it prints out the number.
So, the output of this code will be:
153
370
371
407
These are the four Armstrong numbers between 100 and 999.
相关问题
for i in range(1,10,1):
```python
for i in range(1, 10, 1):
print(i)
```
输出结果为:
1
2
3
4
5
6
7
8
9
这段代码使用了`for`循环和`range()`函数来遍历从1到9的整数。`range(1, 10, 1)`表示从1开始,到10结束(不包括10),步长为1。在循环中,每次迭代时,变量`i`会依次被赋值为1、2、3、4、5、6、7、8、9,并打印出来。
for k in range(1:6):
在 Python 中,range() 函数的参数不能用冒号分隔。应该用逗号来分隔起始值、终止值和步长,如下所示:
```python
for k in range(1, 6):
# 循环体
```
这个循环将会迭代从 1 到 5 的整数,不包括终止值 6。如果你想包括 6,可以把终止值设为 7,如下所示:
```python
for k in range(1, 7):
# 循环体
```
这个循环将会迭代从 1 到 6 的整数,包括终止值 6。