for a in range (1,10): for b in range (1,10): for c in range (1,10): s1=a*100+b*10+c s2=a**3+b**3+c**3 if s1==s2: print (s1)

This code is written in Python and it prints out all the Armstrong numbers between 100 and 999.

An Armstrong number is a number that is equal to the sum of its own digits raised to the power of the number of digits in the number.

For example, 153 is an Armstrong number because:

1^3 + 5^3 + 3^3 = 1 + 125 + 27 = 153

The code uses three nested loops to generate all three-digit numbers from 100 to 999. For each number, it calculates the sum of its digits raised to the third power and compares it to the original number. If they are equal, it prints out the number.

So, the output of this code will be:

153
370
371
407

These are the four Armstrong numbers between 100 and 999.

相关问题

A.for x in range(10):print(x) B. for (x) in range(10):print(x) C. for x in range(10): D. for x in range(10): print(x) print(x)

正确的代码是：

D.

for x in range(10):
    print(x)
    print(x)

在选项 D 中，代码块中的两个 `print(x)` 语句都在循环体内，因此会在每次迭代中分别打印当前的 `x` 值两次，总共输出 20 行数字。而选项 A 和 C 中，只有一个 `print(x)` 语句在循环体内，因此只会输出 10 行数字。选项 B 中的括号是多余的，不符合 Python 语法。

#在 上补充代码 import random s-input(“请输入随机种子：” 15 = 11 for i in range (26): Is.append (chr(ord ('a') +i)) for i in range(10): Is.append (chr( (1)_ random.seed( (2) for i in range (10): for j in range(8): print( (3) print0

对不起，上面的代码有些错误，以下是正确的代码：

import random

s = input("请输入随机种子：")
random.seed(s)

char_set = []
for i in range(26):
char_set.append(chr(ord('a') + i))
for i in range(10):
char_set.append(str(i))

for i in range(10):
code = ''
for j in range(8):
code += random.choice(char_set)
print(code)